-7z^7(-19z^7) = (-7 x -19) x z^(7 + 7) = 133z^14
Answer:
Hence after 3.98 sec i.e 4 sec Object will hit the ground .
Step-by-step explanation:
Given:
Height= 6 feet
Angle =28 degrees.
V=133 ft/sec
To Find:
Time in seconds after which it will hit the ground?
Solution:
<em>This problem is related to projectile motion for objec</em>t
First calculate the Range for object and it is given by ,
(2Ф)/
Here R= range g= acceleration due to gravity =9.8 m/sec^2
1m =3.2 feet
So 9.8 m, equals to 9.8 *3.2=31.36 ft
So g=31.36 ft/sec^2. and 2Ф=2(28)=56


fts
Now using Formula for time and range as

Vx is horizontal velocity
Ф
(28)
ft/sec
So above equation becomes as ,


T is approximately equals to 4 sec.
Answer:
a ≈ 1.8
Step-by-step explanation:
a / sin (180 - 105 - 15)° = 2 /sin 105°
a = (2 /sin 105°) x sin 60°
a = (2 / 0.97) x 0.87
a = 1.79 (≈ 1.8)
So you would do is take 3,500 and multiply it by 4% to get 140
Answer:
213 in base 4 = 124 in base 5
Step-by-step explanation:
First we convert base 4 to base 10
213 in base 4
2*42 + 1*41 + 3*40
32 + 4 + 3
39 in base 10
Now we convert base 10 to base 5
39/5
7/5 r = 4
1 r = 2
124 in base 5
Hence 213 in base 4 = 124 in base 5