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IceJOKER [234]
2 years ago
14

2(2x) + 10 = 3x + 13 Please help

Mathematics
2 answers:
Dima020 [189]2 years ago
8 0

Answer:

−3+2(2)=3

Step-by-step explanation:

2(2)+10=3+13

2(2x)+10−10=3+13−10

zlopas [31]2 years ago
5 0

Answer:

x = 3

Step-by-step explanation:

:))

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Nat2105 [25]
3 x 2.7 is the same as 3 x 3 x 0.9 = 9 x 0.9 = 8.1
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A random sample of 49 measurements from one population had a sample mean of 15, with sample standard deviation 5. An independent
kotykmax [81]

Answer:

Comparing the p value with the significance level \alpha=0.01 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, and the difference between the two groups is significantly different.  

Step-by-step explanation:

\bar X_{1}=15 represent the mean for sample 1

\bar X_{2}=18 represent the mean for sample 2

s_{1}=5 represent the sample standard deviation for 1  

s_{f}=6 represent the sample standard deviation for 2  

n_{1}=49 sample size for the group 2  

n_{2}=64 sample size for the group 2  

\alpha=0.01 Significance level provided

t would represent the statistic (variable of interest)  

Concepts and formulas to use  

We need to conduct a hypothesis in order to check if the difference in the population means, the system of hypothesis would be:  

Null hypothesis:\mu_{1}-\mu_{2}=0  

Alternative hypothesis:\mu_{1} - \mu_{2}\neq 0  

We don't have the population standard deviation's, so for this case is better apply a t test to compare means, and the statistic is given by:  

t=\frac{(\bar X_{1}-\bar X_{2})-\Delta}{\sqrt{\frac{s^2_{1}}{n_{1}}+\frac{s^2_{2}}{n_{2}}}} (1)

And the degrees of freedom are given by df=n_1 +n_2 -2=49+64-2=111  

t-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

With the info given we can replace in formula (1) like this:  

t=\frac{(15-18)-0}{\sqrt{\frac{5^2}{49}+\frac{6^2}{64}}}}=-2.897

P value

Since is a bilateral test the p value would be:  

p_v =2*P(t_{111}  

Comparing the p value with the significance level \alpha=0.01 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, and the difference between the two groups is significantly different.  

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3 years ago
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prohojiy [21]
Answers:
Diameter - B)
Circumference - F)
Radius - C) or <span>E)*</span>
Secant - E) or C)*
Concentric circles - D)
Arc - A)

* Please, note that you described option C and option E with the same exact words. One of the two is supposed to be different.

Let's see the definition of each term of the list on the left in order to find the right description:

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9514 1404 393

Answer:

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Step-by-step explanation:

It can work reasonably well to start with the largest square less than the target number, repeating that approach for the remaining differences. When more squares than necessary are asked for, then the first square chosen may need to be the square of a number 1 less than the largest possible.

The approach where a cube is required can work the same way.

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Answer:

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