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bezimeni [28]
3 years ago
15

Write three solutions for the inequality 13 - 8X < -11

Mathematics
1 answer:
pishuonlain [190]3 years ago
5 0

Answer:

x > 3

-x < -3

3 < x

-3 > -x

Step-by-step explanation:

-8x < -24

x > 3

-x<-3

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if the distance from 0 to x on a number line is less than 5, then -5 is negative.. Is the answer always, sometimes, or never.​
Len [333]

Answer:

Sometimes

Step-by-step explanation:

5 0
3 years ago
To park at the airport, drivers must pay a $4 one time fee and $10 per day. Forrest paid $44 to park. How many days did Forrest
3241004551 [841]

Answer:

4 days

Step-by-step explanation:

Create your equation

10x + 4 = 44

10x = 40

x = 4 days

7 0
4 years ago
Read 2 more answers
1. Simplify 2/radical 5
cupoosta [38]
1.  (2√5)/5
2.  -44√7
3.  8√17
4.  -6√3+12

For 1:  Multiply the numerator and denominator by √5:
\frac{2}{\sqrt{5}}\times \frac{\sqrt{5}}{\sqrt{5}}=\frac{2\sqrt{5}}{5}

For 2:  Simplify √112:
√112 = √(2*56) = √(2*2*28) = √(4*4*7) = 2*2√7 = 4√7
Now multiply by the -11 coefficient:
-11(4√7) = -44√7

For 3:  Add the radicals as you would variables that are like terms.

For 4:  Multiply by the conjugate.  The conjugate of the denominator has the same values with the sign of the radical changed:
\frac{6}{\sqrt{3}+2}\times \frac{\sqrt{3}-2}{\sqrt{3}-2}=\frac{6(\sqrt{3}-2)}{(\sqrt{3}+2)(\sqrt{3}-2)}&#10;\\&#10;\\=\frac{6\sqrt{3}-6*2}{\sqrt{3}*\sqrt{3}-2\sqrt{3}+2\sqrt{3}-2*2}&#10;\\&#10;\\=\frac{6\sqrt{3}-12}{3-4}=\frac{6\sqrt{3}-12}{-1}=-6\sqrt{3}+12
7 0
3 years ago
If the scale factor is 5, how many times larger will the scaled copy's area be?
Lady bird [3.3K]

Answer:

25 times

Step-by-step explanation:

Scale factor is the ratio of dimensions of the image and the preimage.

Scale factor = \frac{\text{Side length of image}}{\text{Side length of preimage}}

Since area of a figure is the square of dimensions.

Area = Length × Width

Therefore, area scale factor will be the ratio of square of the dimensions of image and preimage.

Area scale factor = \frac{\text{Area of the image}}{\text{Area of the preimage}}

                             = (Scale factor)²

                             = 5²

                             = 25

Therefore, area of the image will be 25 times the area of the preimage.

4 0
4 years ago
For rhombus GHJK, find m21.
noname [10]
Half angle K is 30 and the center is 90 so that half angle J is 60 and angle H is equal to angle K so half of H is 30 so that half of G is 60

m<1 =60
5 0
3 years ago
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