Answer:
Step-by-step explanation:
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Hope that helps!
Its just a matter of subbing...but keep in mind, for it to be a solution, it has to satisfy all 3 inequalities
x - y > = -4
2x - y < = 5
2y + x > 1
solutions are : (-1,3) and (3,5)
Answer:
4
Step-by-step explanation:
Answer:
The amount of money in Enid bank account can be written as a linear equation.
Ye = Xe + $4*m
where Ye is the money that Enid has in her account, m is the number of months that have passed since she opened it, and Xe is the initial deposit.
For Jim, the equation is similar:
Yj = Xj + $3*m
where Yj and Xj are similar as above.
Between May 15 and December 31 of the same year, we have 7 months (where i am counting December because the deposit is made in the first day of the month).
Then we have that:
Ye = $72 = Xe + $4*7 = Xe + $28
Xe = $72 - $28 = $44
So in May 15, Enid deposited $44.
For Jim we have:
Yj = $72 = Xj + $3*7 = Xj + $21
Xj = $72 - $21 = $51
So in May 15, Jim deposited $51.
Answer:
a). 0.294
b) 0.11
Step-by-step explanation:
From the given information:
the probability of the low risk = 0.60
the probability of the high risk = 0.40
let 
represent no claim
let 
represent 1 claim
let 
represent 2 claim :
For low risk;
so, = (0.80 * 0.60 = 0.48), = (0.15* 0.60=0.09), = (0.05 * 0.60=0.03)
For high risk:
= (0.50 * 0.40 = 0.2), = (0.30 * 0.40 = 0.12) , = ( 0.20 * 0.40 = 0.08)
Therefore:
a), the probability that a randomly selected policyholder is high-risk and filed no claims can be computed as:
b) What is the probability that a randomly selected policyholder filed two claims?
the probability that a randomly selected policyholder be filled with two claims = 0.03 + 0.08
= 0.11
