We know that, in ∆ABC,
∠A+∠B+∠C = 180°
But the triangle is right angled at C
ie., ∠C = 90°
Therefore, ∠A+∠B+ 90° = 180°
⇒ ∠A + ∠B = 90°
Therefore, <u>cos(A + B) = cos 90º = 0</u>
How do I get this graph and how do I get it with multiplicity polynomials
1 answer:
You might be interested in
Given:
The degree of polynomial = 9
Leading coefficient is negative.
To find:
The end behavior of the polynomial.
Solution:
Let the polynomial be P(x).
We have,
Degree of polynomial = 9, which is odd.
Leading coefficient is negative.
If the degree of a polynomial is odd and leading coefficient is negative, then
Therefore, the end behavior of the given polynomial is .