First we need to add the time she takes warming and the time she takes going to the the gym:

Next, we area going to subtract those 45 minutes from the time the game begins:
We can conclude that she should leaver her house at 6:00 pm if she wants to get in time for her 6:45 pm game.
Answer:
Step-by-step explanation:
Putting value of y = 5
4(5)2 - 7(5) - 6
4(25) - 35 - 6
100 - 41
59
Check the picture below.
as you can see in the picture, the "near arc" is x°, and the "far arc", is the leftover from subtracting the arc of 120° and x°, therefore then
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