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Answer: 25% of the offsprings will be heterozygous for both traits
Explanation: A cross between BbFf and bbff will yield 16 offsprings with four different possible genotypes: BbFf, Bbff, bbFf, and bbff. Only BbFf is the genotype that is heterozygous for both traits, and there are four offsprings with BbFf genotype.
Therefore the percentage of the offsprings that are heterozygous for both traits is 4/16 x 100 = 25%
See the punnett square for the details of the dibybrid cross
Answer:
<u> </u><u>The magnitude of the force exerted by the biceps </u><u> is 218.38N</u>
<u>The magnitude of the force exerted by the elbow </u><u> is 194.37N</u>
Explanation:
Firstly , lets calculate the magnitude of force exerted by biceps -
Mass of the forearm=
Mass of the ball =
= 0.950kg
so, weight of the forearm=
g
weight of the ball=
g
Now , balancing torque about the elbow , we have-
(here , distance of the bicep is 2.50cm = 0.025m and distance of the ball is 36cm= 0.36m)
Now putting the given values in the formula -
Now, lets calculate the force exerted by elbow -
Balancing the vertical forces