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postnew [5]
3 years ago
7

What is the answer to the problem? 7 1/2 ÷ 3/4 I need this fast please help!! :)

Mathematics
2 answers:
WARRIOR [948]3 years ago
6 0

Answer:

10

I hope this helps!

irakobra [83]3 years ago
4 0
The answer is 10 I believe.
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A restaurant that can hold 300 people is divided into 20 equal parts. How many people can be put in each section?
alexandr1967 [171]

Answer:

15

Step-by-step explanation:

300/20=15

4 0
3 years ago
Plz help out i am so confused
MatroZZZ [7]

Answer:

Me too not trying to get the points but how are u suppose to solve this anyway

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
What is the maximum number of relative extrema contained in the graph of this function f(x)=3x^3-x^2+4x-2
Sergeeva-Olga [200]
The maximum number of turning points in a cubic function is 2.

In this case,

f(x)=3x^3-x^2+4x-2\implies f'(x)=9x^2-2x+4

The discriminant is (-2)^2-4(9)(4)=-140, which means the derivative has no real roots. This means there are no critical points and thus no turning points/relative extrema.
5 0
3 years ago
Read 2 more answers
4 &lt; x &lt; 7<br> Please give me a proper explanation.
sesenic [268]

An explanation for 4 < x < 7 is that 4 is less than and x is less than 7.

<h3>How to explain the information?</h3>

The mathematical expression that is given is 4 < x < 7. It should be noted that this implies that 4 is less than and x is less than 7.

In this case, the appropriate values that can fit x in this situation will be 5 and 6.

Learn more about less than on:

brainly.com/question/816726

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6 0
2 years ago
5<br> 0 = - in<br> =<br> in quadrant II<br> Given cos =<br> Find sin<br> 3
____ [38]

Answer:

sinΘ = \frac{2}{3}

Step-by-step explanation:

using the identity

sin²x + cos²x = 1  ( subtract cos²x from both sides )

sin²x = 1 - cos²x ( take square root of both sides )

sinx = ± \sqrt{1-cos^2x}

given

cosΘ = - \frac{\sqrt{5} }{3} , then

sinΘ = ± \sqrt{1-(-\frac{\sqrt{5} }{3})^2 }

        = ± \sqrt{1-\frac{5}{9} }

        = ± \sqrt{\frac{4}{9} }

        = ± \frac{2}{3}

since Θ is in quadrant II where sinΘ > 0 , then

sinΘ = \frac{2}{3}

7 0
3 years ago
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