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2 years ago

What is the next number in this sequence? 2, 16, 128, 1024, ___________

Mathematics

1 answer:

TEA [102]2 years ago

5 0

Just multiply by 8 each time hope this helps :)))

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Write the sum or difference in the standard form a + bi. ( 7 + 5i) - ( -9 + i)

Veseljchak [2.6K]

(7 + 5i) - ( -9 + i)
= 7 + 5i - (-9) - (i)
= 7 + 5i + 9 - i
= 16 + 4i

= 4i + 16

3 0

3 years ago

A teachers desk is 5.5 meters long a students desk is 220 centimeters long what is the difference in the length in centimeters b

Mama L [17]

so if 5.5 is in meter let change it to cm because the question want us to give the answer in cm.

$1cm = 0.01meter$

$to \: turn \: meters \: into \: \\ cm \: we \: have \: to \: multiply \: by \: 100$

now we multiply 5.5 times 100 which is equal to 550.

next we subtract 550 - 220= 330.

finally, the difference between a teacher and student is 330cm .meaning the teacher's desk is 330 cm longer or taller than the student.

7 0

2 years ago

500,000 in expanded form

Yuri [45]

Answer:

500,000 =

5 × 100,000

+ 0 × 10,000

+ 0 × 1,000

+ 0 × 100

+ 0 × 10

+ 0 × 1

Step-by-step explanation:

there are more then one ways of writing this so here's another example

500,000 =

500,000

+ 0

5 0

10 months ago

For every left handed person, rhere are about 4 right handed people. If there are 30 students in a class, predoct the number of

hjlf

Answer:

4 right handlers for everytime 5 people

solution:

4/5. = x/30

x = (4)(30)/5

x= 24

there are 24 right handed people

Step-by-step explanation:

I am left handed so I know this is true :)

7 0

4 months ago

PLEASE HELP

lisabon 2012 [21]

Step-by-step explanation:

The figure below shows a portion of the graph of the function $j\left(x\right) \ = \ 4^{x-2}$ , hence the average rate of change (slope of the blue line) between the $x$ and $x+h$ is

$\text{Average rate of change} \ = \ \displaystyle\frac{\Delta y}{\Delta x} \\ \\ \rule{3.7cm}{0cm} = \dsiplaystyle\frac{f\left(x+h\right) \ - \ f\left(x\right)}{\left(x \ + \ h \right) \ - \ x} \\ \\ \\ \rule{3.7cm}{0cm} = \displaystyle\frac{f\left(x + h\right) \ - \ f\left(x\right)}{h} \\ \\ \\ \rule{3.7cm}{0cm} = \displaystyle\frac{4^{x+h-2} \ - \ 4^{x-2}}{h} \\ \\ \\ \rule{3.7cm}{0cm} = \displaystyle\frac{4^{x-2+h} \ - \ 4^{x-2}}{h}$

$\\ \\ \\ \rule{3.7cm}{0cm} = \displaystyle\frac{\left(4^{x-2}\right)\left(4^{h}\right) \ - \ 4^{x-2}}{h} \\ \\ \\ \rule{3.7cm}{0cm} = \displaystyle\frac{\left(4^{x-2}\right)\left(4^{h} \ - \ 1 \right)}{h}$

7 0

1 year ago