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3 years ago

6

a circus performer walks on a tightrope 25 feet above the ground. the tightrope is supported by two beams and two support cables

. if the distance between each beam and the base of its support cable is 15 feet, what is the length of the support cable?

1 answer:

igomit [66]3 years ago

8 0

Check the picture below.

and surely you know how much that is.

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Somebody please help me

Stella [2.4K]

Answer:

(13/24)

Step-by-step explanation:

let’s find a common number that we can get on the denominator

4 can be multiplied to get 48

6 can be multiplied to get 48

and 8 can also be multiplied to get 48

4(12) = 48

so for the equation (1/4) the numerator and denominator will both be multiplied by 12

(1/4)x(12/12) = (12/48)

6(8)= 48

(1/6)x(8/8) = (8/48)

8(6) = 48

(1/8)x(6/6) = (6/48)

now the fractions are

(12/48)+(8/48)+(6/48)

we can add them now because they have the same denominator and we get:

(26/48)

this can be simplified if we divide both the numerator and denominator by 2 and we get

(13/24)

7 0

3 years ago

Read 2 more answers

Initial value problems dy/dx+2y=3. Y(0)=1

Pavel [41]

The initial value equation is $y = \frac 12(3 - e^{-2x})$

<h3>How to solve the initial value?</h3>

The equation is given as:

$\frac{dy}{dx} +2y = 3$

Where

Y(0) = 1

Subtract 2y from both sides in the equation

$\frac{dy}{dx} = -2y + 3$

Rewrite as:

$\frac{dy}{-2y + 3} = dx$

Integrate both sides of the equation

$-\frac 12\ln|-2y + 3| = x + C_o$

Multiply through by -2

$\ln|-2y + 3| = -2x + C_1$

Take the exponent of both sides

$-2y + 3 = Ce^{-2x$

Next, we solve for C under the initial condition Y(0) = 1.

This gives

$-2(1) + 3 = Ce^{-2 * 0$

Evaluate

-2 + 3 = C

Solve for C

C = 1

Substitute C = 1 in $-2y + 3 = Ce^{-2x$

$-2y + 3 = e^{-2x$

Next, we solve for y

$y = \frac 12(3 - e^{-2x})$

Hence, the initial value equation is $y = \frac 12(3 - e^{-2x})$

Read more about initial value at:

brainly.com/question/16945606

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3 0

1 year ago

John's Bikes uses the retail inventory method. Sales at retail were $120,000. Net purchases were $68,000 at cost and $124,000 at

photoshop1234 [79]

The answer will be a

4 0

3 years ago

a square garden with a side of 150m has a square swimming pool in the very center with a side length of 25m calculate the area o

marta [7]

Answer: 21,875 sqm

Step-by-step explanation:

Step 1:

Find the gross area of the garden.

Square 150m = 22,500 sqm.

Step 2:

Find the area of the pool.

Square 25m = 625 sqm.

Step 3:

Subtract the area of the pool from the gross area of the garden

to find the net area of the garden.

22,500 - 625 = 21,875 sqm.

Warning:

Do not subtract the side length of the swimming pool from the side length

of the garden before squaring.

7 0

3 years ago

The graph of an absolute value function opens down and has a vertex of (0, -3). The domain of the function is . The range of the

Firdavs [7]

Answer:

Domain: All real numbers

Range: $y\leq -3$

Step-by-step explanation:

The domain is the set of all x values. The quadratic equation continue to operate over all x-values in both directions. The domain is all real numbers.

The range is the set of all y-values. Here the quadratic begins at -3 and continues in a downward direction forever. Then range is $y\leq -3$

6 0

3 years ago