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Vladimir79 [104]
3 years ago
12

Find the LCM of 4 and 9 A. 9 B. 35 C. 72 D. none of the above

Mathematics
2 answers:
Vitek1552 [10]3 years ago
7 0
B is the answer becuase it’s 35 and that should be correct
Alenkinab [10]3 years ago
7 0

Answer:

neither, its 36 actually

Step-by-step explanation:

You might be interested in
Simplify 2(x - 4) + 7(x + 2).
Sauron [17]

Answer:

9x+6

Step-by-step explanation:

2(x-4)= 2x-8

7(x+2)= 7x+14

2x-8+7x+14

clt

9x6

3 0
3 years ago
Hi pls, help me with this, I am giving 15 points 10 for answering the question and 5 for telling me what is Q1 meaning and Q2 me
stepladder [879]

Answer:

we have to put the numbers in order..

(121,122,125, 126,132),M,(135,136,136,138,140)

Step-by-step explanation:

minimum : (smallest number) = 121

Q1 : 125

Q2 (median) : (132 + 135) / 2 = 267/2 = 133.5

Q3 : 136

maximum : (largest number) = 140

I did this a long time ago so im not so sure

8 0
2 years ago
Read 2 more answers
Find the area of the triangle defined by the coordinates (7, 1), (0, 10), and (9, 4). (To the nearest tenth)
slega [8]

Answer:

  C)  19.5 square units

Step-by-step explanation:

The area from coordinates can be computed as ...

  A = (1/2)|x1(y2 -y3) +x2(y3 -y1) +x3(y1 -y2)|

  = (1/2)|7(10 -4) +0(4 -1) +9(1-10)| = (1/2)|7·6 +9·(-9)|

  = (1/2)|-39| = 39/2 = 19.5

The area of the triangle is 19.5 square units.

4 0
3 years ago
Read 2 more answers
Albert wants to buy two pomegranates and some peaches • The price of one pomegranate is $1.59. • The price of peaches is $1.19 p
viktelen [127]

Answer:

He can buy 5 pounds of peaches.

Step-by-step explanation:

2 pomegranates cost $3.18 so, subtract that from $10.00 and you get $6.82. Multiply the different number of pounds with the cost per pound until you go over $6.82. Then go back a pound and multiply. 5 pounds times $1.19 equals $5.95.

7 0
3 years ago
Please could you find the answers to the questions in the attachment.
Fudgin [204]
(\frac{x1+x2}{2} , \frac{y1+y2}{2})we need 3 equations
1. midpoint equation which is  (\frac{x1+x2}{2} , \frac{y1+y2}{2}) when you have 2 points

2. distance formula which is D= \sqrt{(x2-x1)^{2}+(y2-y1)^{2}}

3. area of trapezoid formula whhic is (b1+b2) times 1/2 times height


so

x is midpoint of B and C
B=11,10
c=19,6
x1=11
y1=10
x2=19
y2=6
midpoint=(\frac{11+19}{2} , \frac{10+6}{2})
midpoint=(\frac{30}{2} , \frac{16}{2})
midpoint= (15,8)

point x=(15,8)



y is midpoint of A and D
A=5,8
D=21,0
x1=5
y1=8
x2=21
y2=0
midpoint=(\frac{5+21}{2} , \frac{8+0}{2})
midpoint=(\frac{26}{2} , \frac{8}{2})
midpoint=(13,4)

Y=(13,4)



legnths of BC and XY
B=(11,10)
C=(19,6)
x1=11
y1=10
x2=19
y2=6
D= \sqrt{(19-11)^{2}+(6-10)^{2}}
D= \sqrt{(8)^{2}+(-4)^{2}}
D= \sqrt{64+16}
D= \sqrt{80}
D= 4 \sqrt{5}
BC=4 \sqrt{5}





X=15,8
Y=(13,4)
x1=15
y1=8
x2=13
y2=4
D= \sqrt{(13-15)^{2}+(4-8)^{2}}
D= \sqrt{(-2)^{2}+(-4)^{2}}
D= \sqrt{4+16}
D= \sqrt{20}
D= 2 \sqrt{5}
XY=2 \sqrt{5}


the thingummy is a trapezoid
we need to find AD and BC and XY
we already know that BC=4 \sqrt{5} and XY=2 \sqrt{5}

AD distance
A=5,8
D=21,0
x1=5
y1=8
x2=21
y2=0
D= \sqrt{(21-5)^{2}+(0-8)^{2}}
D= \sqrt{(16)^{2}+(-8)^{2}}
D= \sqrt{256+64}
D= \sqrt{320}
D= 4 \sqrt{2}
AD=4 \sqrt{2}


so we have
AD=4 \sqrt{2}
BC=4 \sqrt{5} 
XY=2 \sqrt{5}

AD and BC are base1 and base 2
XY=height
so
(b1+b2) times 1/2 times height
(4 \sqrt{2}+4 \sqrt{5}) times 1/2 times 2 \sqrt{5} =
(4 \sqrt{2}+4 \sqrt{5}) times \sqrt{5} [/tex] =
4 \sqrt{10}+4*5=4 \sqrt{10}+20=80 \sqrt{10}=252.982


























X=(15,8)
Y=(13,4)
BC=4 \sqrt{5}
XY=2 \sqrt{5}
Area=80 \sqrt{10} square unit or 252.982 square units







7 0
3 years ago
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