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3 years ago

Find the LCM of 4 and 9 A. 9 B. 35 C. 72 D. none of the above

Mathematics

2 answers:

Vitek1552 [10]3 years ago

7 0

B is the answer becuase it’s 35 and that should be correct

Alenkinab [10]3 years ago

7 0

Answer:

neither, its 36 actually

Step-by-step explanation:

You might be interested in

Simplify 2(x - 4) + 7(x + 2).

Sauron [17]

Answer:

9x+6

Step-by-step explanation:

2(x-4)= 2x-8

7(x+2)= 7x+14

2x-8+7x+14

clt

9x6

3 0

3 years ago

Hi pls, help me with this, I am giving 15 points 10 for answering the question and 5 for telling me what is Q1 meaning and Q2 me

stepladder [879]

Answer:

we have to put the numbers in order..

(121,122,125, 126,132),M,(135,136,136,138,140)

Step-by-step explanation:

minimum : (smallest number) = 121

Q1 : 125

Q2 (median) : (132 + 135) / 2 = 267/2 = 133.5

Q3 : 136

maximum : (largest number) = 140

I did this a long time ago so im not so sure

8 0

2 years ago

Read 2 more answers

Find the area of the triangle defined by the coordinates (7, 1), (0, 10), and (9, 4). (To the nearest tenth)

slega [8]

Answer:

C) 19.5 square units

Step-by-step explanation:

The area from coordinates can be computed as ...

A = (1/2)|x1(y2 -y3) +x2(y3 -y1) +x3(y1 -y2)|

= (1/2)|7(10 -4) +0(4 -1) +9(1-10)| = (1/2)|7·6 +9·(-9)|

= (1/2)|-39| = 39/2 = 19.5

The area of the triangle is 19.5 square units.

4 0

3 years ago

Read 2 more answers

Albert wants to buy two pomegranates and some peaches • The price of one pomegranate is $1.59. • The price of peaches is $1.19 p

viktelen [127]

Answer:

He can buy 5 pounds of peaches.

Step-by-step explanation:

2 pomegranates cost $3.18 so, subtract that from $10.00 and you get $6.82. Multiply the different number of pounds with the cost per pound until you go over $6.82. Then go back a pound and multiply. 5 pounds times $1.19 equals $5.95.

7 0

3 years ago

Please could you find the answers to the questions in the attachment.

Fudgin [204]

( $\frac{x1+x2}{2} , \frac{y1+y2}{2}$ )we need 3 equations
1. midpoint equation which is ( $\frac{x1+x2}{2} , \frac{y1+y2}{2}$ ) when you have 2 points

2. distance formula which is D= $\sqrt{(x2-x1)^{2}+(y2-y1)^{2}}$

3. area of trapezoid formula whhic is (b1+b2) times 1/2 times height

so

x is midpoint of B and C
B=11,10
c=19,6
x1=11
y1=10
x2=19
y2=6
midpoint=( $\frac{11+19}{2} , \frac{10+6}{2}$ )
midpoint=( $\frac{30}{2} , \frac{16}{2}$ )
midpoint= (15,8)

point x=(15,8)

y is midpoint of A and D
A=5,8
D=21,0
x1=5
y1=8
x2=21
y2=0
midpoint=( $\frac{5+21}{2} , \frac{8+0}{2}$ )
midpoint=( $\frac{26}{2} , \frac{8}{2}$ )
midpoint=(13,4)

Y=(13,4)

legnths of BC and XY
B=(11,10)
C=(19,6)
x1=11
y1=10
x2=19
y2=6
D= $\sqrt{(19-11)^{2}+(6-10)^{2}}$
D= $\sqrt{(8)^{2}+(-4)^{2}}$
D= $\sqrt{64+16}$
D= $\sqrt{80}$
D= $4 \sqrt{5}$
BC= $4 \sqrt{5}$

X=15,8
Y=(13,4)
x1=15
y1=8
x2=13
y2=4
D= $\sqrt{(13-15)^{2}+(4-8)^{2}}$
D= $\sqrt{(-2)^{2}+(-4)^{2}}$
D= $\sqrt{4+16}$
D= $\sqrt{20}$
D= $2 \sqrt{5}$
XY= $2 \sqrt{5}$

the thingummy is a trapezoid
we need to find AD and BC and XY
we already know that BC= $4 \sqrt{5}$ and XY= $2 \sqrt{5}$

AD distance
A=5,8
D=21,0
x1=5
y1=8
x2=21
y2=0
D= $\sqrt{(21-5)^{2}+(0-8)^{2}}$
D= $\sqrt{(16)^{2}+(-8)^{2}}$
D= $\sqrt{256+64}$
D= $\sqrt{320}$
D= $4 \sqrt{2}$
AD= $4 \sqrt{2}$

so we have
AD= $4 \sqrt{2}$
BC= $4 \sqrt{5}$
XY= $2 \sqrt{5}$

AD and BC are base1 and base 2
XY=height
so
(b1+b2) times 1/2 times height
( $4 \sqrt{2}+4 \sqrt{5}$ ) times 1/2 times $2 \sqrt{5}$ =
( $4 \sqrt{2}+4 \sqrt{5}$ ) times \sqrt{5} [/tex] =
$4 \sqrt{10}+4*5$ = $4 \sqrt{10}+20$ =80 $\sqrt{10}$ =252.982

X=(15,8)
Y=(13,4)
BC= $4 \sqrt{5}$
XY= $2 \sqrt{5}$
Area=80 $\sqrt{10}$ square unit or 252.982 square units

7 0

3 years ago