(2,5) , (6,8)
Distance formula :
d = √(x₂-x₁)² + (y₂-y₁)²
Simply plug in the values.
d = √(6 - 2)² + (8 - 5)²
Simplify.
d = √(4)² + (3)²
Simplify.
d = √16 + 9
Simplify.
d = √25
So, the distance is 5
~Hope I helped!~
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Answer:
2
Step-by-step explanation:
Get the derivative:
<em>y</em> = (9 - <em>x</em>²)¹ʹ³
d<em>y</em>/d<em>x</em> = 1/3 (9 - <em>x</em>²)⁻²ʹ³ d/d<em>x</em> [9 - <em>x</em>²]
d<em>y</em>/d<em>x</em> = 1/3 (9 - <em>x</em>²)⁻²ʹ³ (-2<em>x</em>)
d<em>y</em>/d<em>x</em> = -2/3 <em>x</em> (9 - <em>x</em>²)⁻²ʹ³
Evaluate it at <em>x</em> = 1 :
d<em>y</em>/d<em>x</em> (1) = -2/3 • 8⁻²ʹ³
Since 8 = 2³, we have
8⁻²ʹ³ = 1 / 8²ʹ³ = 1 / (2³)²ʹ³ = 1 / 2² = 1/4
Then the tangent line has equation
<em>y</em> - 2 = 1/4 (<em>x</em> - 1) → <em>y</em> = 1/4 <em>x</em> + 7/4
