Which of the following....

Harley graphs a polygon that is located entirely inside quadrant l. He rotates the figure clockwise 90 about the origin and then

lbvjy [14]

Answer:

Chorus 1]

Bm-Tha-A-Tha-Ay-Bm-Bm

Na-a-No-os-the-A

Bm-Tha-Ay-Bm-Nos-Bm-the-A-pt-Bm

Bm-Tha-A-Tha-Ay-Bm-Bm

Na-a-No-os-the-A

Bm-Tha-A-Bm-Na-a-Bm-Bm-pt

[Hook]

Ya'll gone (pt) make me act a fool, (pt) up (B) in (pt) here, (B) up (B) in h! (pt)

Ya'll gone (pt) make me loose my (pt) cool, up in here, (pt) up in here! (pt)

Ya'll gone make (pt) me bust a (pft) sweat, up in here, (pt) up in here! (pt)

Ya'll gone make (pt) my fingers snap, (pt) up in here, (pt) up in here! (pt)

[Verse 1]

Why should I battle a krusty old man

When you can't even defeat a little weak Peter Pan

Ya (B) lucky this is (pt) only a beatbox (pt) battle

Cause in a real battle (pt) I make ya feel rattled

[Verse 2]

Look at him, (pt) he only got one planet, (pt)

I got the whole Galaxy (pt) under my dependence, (pt)

You're gonna beg (pt) when you (B) bleed and die, (pt)

As you realize (pt) destiny arrived

[Pre-Chorus]

(B) Ya'll gone (pt) make me-sla-Bea-pt-ha-sss-ssslipita-pa-a-pt-A-prdrdrdr-prdrdrdr (pt) ha-tugh-ha

(B) Ya'll gone (pt) make (B) me-tugh-ha-Bea-pt-ha-sss-ssslipita-pa-a-pt-ki-prrsk-kt-Bea-pt-ka-tugh

(B) Ya'll gone (pt) make me-sla-Bea-pt-ha-sss-ssslipita-pa-a-pt-A-prdrdrdr-prdrdrdr (pt) ha-tugh-ha

(B) Ya'll gone (pt) make (B) me-tugh-ha-Bea-pt-ha-sss-ssslipita-pa-a-pt-ki-prrsk-kt-Bea-pt-ka-tugh

[Chorus 2]

Bm-Tha-A-Tha-Ay-Bm-Bm

Na-a-No-os-the-A

Bm-Tha-Ay-Bm-Nos-Bm-the-A-pt-Bm

Bm-Tha-A-Tha-Ay-Bm-Bm

Na-a-No-os-the-A

Bm-Tha-A-Bm-Na-a-Bm-Bm-pt

[Post-Chorus]

Let me show you how to scratch it!-pt-ha-Tugh-ha

Bm-Tha-A-pt-et-The-Bea-et-The-Ba-A-pt-A-Tha-A

Bm-Tha-A-pt-et-The-PRRRSK-kt-Bea-pt-Ha-tugh-Ha

Bm-Tha-A-pt-et-The-Bea-et-The-Ba-A-pt-A-Tha-A-Bm

Either way, destiny still arrives

Beeeeww!!

Step-by-step explanation:

4 0

3 years ago

Please help me asapppppppppppppppppppppp :)))))))))))))))))))

Reptile [31]

Answer: X is 15. N is 100

6 0

3 years ago

Mark and his friends order two pizzas of the same size .•The first pizza is cut into 6 slices of equal size .•The second pizza i

nydimaria [60]

Mark is correct because taking a slice from each pizza would be 3/6 or 1/2 of the pizza but taking two slices of the first pizza, Mark wouldn't get as much because that is the same as 2/6 or 1/3 of the pizza. 1/2 > 1/3 therefore Marks conclusion is correct.

6 0

3 years ago

A cube has a side length of 5 centimeters. What is its surface area of the cube?

balandron [24]

Total surface area of the cube = 6.x^2.

= 6. (5)^2 cm^2

= 150cm^2. Answer.

5 0

3 years ago

Read 2 more answers

We take a milk carton from the refrigerator and put it on the table at room temperature. We assume that the temperature of the c

Kisachek [45]

We can solve this problem using separation of variables.

Then apply the initial conditions

EXPLANATION

We were given the first order differential equation

$\frac{dT}{dt}=k(T-a)$

We now separate the time and the temperature variables as follows,

$\frac{dT}{T-a}=kdt$

Integrating both sides of the differential equation, we obtain;

$ln(T-a)=kt +c$

This natural logarithmic equation can be rewritten as;

$T-a=e^{kt +c}$

Applying the laws of exponents, we obtain,

$T-a=e^{kt}\times e^{c}$

$T-a=e^{c}e^{kt}$

We were given the initial conditions,

$T(0)=4$

Let us apply this condition to obtain;

$4-20=e^{c}e^{k(0)}$

$-16=e^{c}$

Now our equation, becomes

$T-a=-16e^{kt}$

or

$T=a-16e^{kt}$

When we substitute a=20,
we obtain,

$T=20-16e^{kt}$

b) We were also given that,

$T(5)=8$

Let us apply this condition again to find k.

$8=20-16e^{5k}$

This implied

$-12=-16e^{5k}$

$\frac{-12}{-16}=e^{5k}$

$\frac{3}{4}=e^{5k}$

We take logarithm to base e of both sides,

$ln(\frac{3}{4})=5k$

This implies that,

$\frac{ln(\frac{3}{4})}{5}=k$

$k=-0.2877$

After 15 minutes, the temperature will be,

$T=20-16e^{-0.2877\times 15}$

$T=20-0.21376$

$T=19.786$

After 15 minutes, the temperature is approximately 20°C

6 0

3 years ago