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strojnjashka [21]
3 years ago
6

Solve for line segment AB

Mathematics
1 answer:
Molodets [167]3 years ago
5 0

Answer:

AB = 32

Step-by-step explanation:

Given:

AD = 40

CD = 9

Required:

Find the length of segment AB

Solution:

BC and CD are radius of the circle. Therefore,

BC = CD = 9

AB = AC - BC

AB = AC - 9

We need to find AC

Since AD is tangent, CD is perpendicular to AD, this means that <D is a right angle. This makes ∆ADC a right triangle.

Therefore, we can apply Pythagorean theorem to find AC.

Thus:

AC² = AD² + CD²

AC² = 40² + 9²

AC² = 1,681

AC = √1,681

AC = 41

Let's find BC:

AB = AC - 9

Plug in the value of AC

AB = 41 - 9

AB = 32

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The data represents the number of runs allowed by 8 college softball pitchers. {18, 49, 38, 41, 33, 44, 42, 22}
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This Question is incomplete

Complete Question:

The data represents the number of runs allowed by 8 college softball pitchers. {18, 49, 38, 41, 33, 44, 42, 22}

What is the five number summary:

a) Minimum

b) Q₁

c) Median

d) Q₃

e) Maximum

Answer:

a) Minimum = 18

b) Q₁ = 27.5

c) Median = 39.5

d) Q₃ = 43

e) Maximum = 49

Step-by-step explanation:

From the above diagram, we were given the following set of data.

{18, 49, 38, 41, 33, 44, 42, 22}

Before answering any of the questions, we have to rearrange the data from the lowest to the highest (ascending order). Hence, we have:

{18, 22, 33, 38, 41, 42, 44, 49}

a) Minimum

{18, 22, 33, 38, 41, 42, 44, 49}

Looking at this set of arranged data, the minimum number is the least or lowest number.

This number is 18

b) Q₁

{18, 22, 33, 38, 41, 42, 44, 49}

Q₁ means First Quartile. The formula is = ¼(n + 1)th value

n = Number of terms in the data set = 8

= ¼(8 + 1)th value

= ¼(9)th value

= 2 1/4 value

= 2.25 value

In the above Question, the 2.25 value is the value between the second and third number.

Hence:

22+33/2 = 55/2 = 27.5

Therefore, Q₁ = 27.5

c) Median

{18, 22, 33, 38, 41, 42, 44, 49}

The median of the number is the number in the middle

For this data, we have 8 number, Hence the median is the sum of the 4th and 5th term divided by 2

4th term = 38

5th term = 41

= 38 + 41/ 2 = 79/2

= 39.5

Hence, the median = 39.5

d) Q₃

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Q₃ means Third Quartile. The formula is = ¾(n + 1)th value

n = Number of terms in the data set = 8

= ¾(8 + 1)th value

= ¾(9)th value

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= 6.75 value

In the above Question, the 6.75 value is the value between the sixth and seventh number.

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Therefore, Q₃ = 43

e) Maximum

{18, 22, 33, 38, 41, 42, 44, 49}

Looking at this set of arranged data, the Maximum number is the highest number.

This number is 49

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