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Ainat [17]
3 years ago
5

HELP HELP HELP HELP HELP HELP plsssssss¡!

Mathematics
1 answer:
mylen [45]3 years ago
7 0

Answer:

$201.60

Step-by-step explanation:

12% of 180 = 21.6

Cost of health club = 180

180 + 21.6 = $201.60

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Need help asap please!!<br> This is the only one i don’t know i’m stuck!
lyudmila [28]

Answer:

Reminder that is this form  a(b)^x  where  a > 0

When   b > 0  but < 1 that is a decay function

When   b > 1 than its a growth function

Step-by-step explanation:

So following this you can figure out the answer

g(x)=0.3(x)      

this is neither since there is no exponent (linear)

H=72(56)^t    

this is growth since b  = 56

A=(43)^t        

this is growth since b  = 43 ("a" is understood as "1")

H=5.9(0.82)^t      

this is decay since b =  0.82

y=0.8(3.6)^t      

this is growth since b = 3.6

f(t)=0.72(15)^t    

this is growth since b  = 14  

A=49(8)^t      

this is growth since b  = 8

6 0
3 years ago
How do you break apart 3 x 5
Burka [1]
You have to separate 3 five times so like 3+3+3+3+3=15
6 0
4 years ago
A florist must make 5 identical
Sonbull [250]

Answer:

A. 40x + 10y + 10z = $160

B. 8 Roses, 2 lilies and 2 irises

C.

1. 20x + 5y + 5z = $80

2. 4x + y + z = $16

3. 8x + 2y + 2z = $32

Step-by-step explanation:

Cost for each flower = $160/5 = $32

So we have $32 for each bouquet consisting of 12 flowers each.

Roses = x = $2.50 each

lilies = y = $4 each

irises = z = $2 each

8x + 2y + 2z = $32

8($2.50) + 2($4) + 2($2) = $32

$20 + $8 + $4 = $32

$32 = $32

a. Maximum budget is $160

40x + 10y + 10z = $160

40($2.50) + 10($4) + 10($2) = $160

$100 + $40 + $20 = $160

$160 = $160

b. From above

8x + 2y + 2z = $32

8 Roses, 2 lilies and 2 irises

c. No. There are other solutions If total cost is not limited

1. 20x + 5y + 5z

20($2.50) + 5($4) + 5($2)

$50 + $20 + $10

= $80

2. 4x + y + z

4($2.50) + $4 + $2

$10 + $4 + $2

= $16

3. 8x + 2y + 2z

8($2.50) + 2($4) + 2($2)

$20 + $8 + $4

= $32

7 0
3 years ago
Please help me with this!!!
RSB [31]
The answer that you have is most likely right, since the grouping did not change.
4 0
3 years ago
Just checking this... It would be C right?
DerKrebs [107]

Answer: yes it is

Step-by-step explanation:

7 0
4 years ago
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