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Assoli18 [71]
3 years ago
5

Please help it'll mean a lot :) <33​

Mathematics
1 answer:
gavmur [86]3 years ago
3 0
Your answer is C because 12•10= 12
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Match with the sum of the monomial and binomial. Tiles 2x2y + (x2y − 2xy2) (5xy2 − x2y) + 3x2y 4x2y + (x2y + xy2) x2y + (-2xy2 −
SVETLANKA909090 [29]
<h2>Answer:</h2>

We will simply solve them and get correct answers that will match the answers provided.

1.  2x^{2}y+(x^{2}y-2xy^{2} )

= 3x^{2} y-2xy^{2}

2. (5xy^{2}-x^{2} y)+3x^{2} y

= 5xy^{2} +2x^{2} y

3. 4x^{2} y+(x^{2} y+xy^{2} )

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4. x^{2} y+(-2xy^{2}-4x^{2} y)

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3 0
4 years ago
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PLEASE please help me out!!!!!! :)
Molodets [167]

The feasible region is shown in the picture above. The horizontal axis is the X axis.

If you now draw a family of lines parallel to 5x+4y=C through the region, increasing $C$, that is, the X-intercept, we will have the maximum value of $C$ when the line passes through the endpoint $(-2,6)$ .

Hence, $C=5(-2)+4(6)=14$

7 0
3 years ago
Which shows .51 and .069 in fraction form in equal denominator.
Marina CMI [18]
A. Shows it in fraction form
8 0
4 years ago
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What is the HCF of 1280 and 630
tatuchka [14]

Given:

The two numbers are 1280 and 630.

To find:

The HCF of the given numbers.

Solution:

First write the given numbers in prime factorization form.

1280=2\cdot 2\cdot 2\cdot 2\cdot 2\cdot 2\cdot 2\cdot 2\cdot 5

630=2\cdot 3\cdot 3\cdot 5\cdot 7

Now the product of all the common prime factors is known as the HCF of 1280 and 630.

HCF=2\cdot 5

HCF=10

Therefore, the HCF of 1280 and 630 is 10.

4 0
3 years ago
5.) What is the quotient of 15.26 and 3.5?
elena55 [62]

Answer:

I got 18.26

Step-by-step explanation:

Added them up

3 0
4 years ago
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