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posledela
3 years ago
15

Suppose that a ball is dropped from the upper observation deck of the CN Tower in Toronto, 450 m above the ground. Find the velo

city of the ball after 2 seconds. Through experiments carried out four centuries ago, Galileo discovered that the distance fallen by any freely falling body is proportional to the square of the time it has been falling. (This model for free fall neglects air resistance.) If the distance fallen after t seconds is denoted by s ( t ) and measured in meters, then Galileo's law is expressed by the equation
Physics
1 answer:
densk [106]3 years ago
6 0

Answer:

v = -19.6 m / s,    y =y₀ + v₀ t - ½ g t²

Explanation:

This is an exercise in kinetics in one dimension, let's take the upward direction as positive

           v = v₀ - g t

in this case as the body is released its initial velocity is zero and the acceleration is -g the sign indicates that it is directed downwards

           v = 0 -g t

           v = - 9.8 2

            v = -19.6 m / s

the sign indicates that the speed is down.

Galileo's equation is

            y =y₀ + v₀ t - ½ g t²

where i is the initial height, v₀ the initial velocity and -g the acceleration of the body

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archer shoots his arrow towards a target at a distance of 90 m, and hits ‘bullseye’ . Calculate the acceleration and time taken
mario62 [17]

Answer:

a =45 m/s2

t = 2 seconds

Explanation:

Hi, to answer this question we have to apply the next formula:

v^2 = u^2 +2 a d

Where:

v = final velocity = 90 m/s

u = initial velocity = 0 m/s (shots from rest)

a = acceleration (m/s2)

d = distance = 90m

90^2 = 0^2 + 2a(90)

Solving for a:

8,100= 180 a

8,100/180 = a

a = 45 m/s^2

For time:

v = u + at

90 = 0 + 45t

90/45=t

t =2 seconds

6 0
3 years ago
A jet, sitting on the runway, takes off and accelerates at 8.0 m/s for 16s. How far did the jet travel down the runway?
nydimaria [60]

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2.4 m/s". 1

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A jet with mass m = 8 x 10* kg jet accelerates down the runway for takeoff at 2.4 m/s". 1

8 0
3 years ago
8. Ella wants to replace old bulbs of her home with new LED bulbs. She buys LED bulb that has inbuilt AC to DC converter of outp
tankabanditka [31]

The power dissipated by the LED is 20 Watts and the work done for 1 hour 15 minutes is 56.25 kJ.

<h3>What is electrical power?</h3>

Electrical power is the rate at which electrical work is done.

  • Electrical power = voltage × current

The LED is 75% efficient means that 75% of power dissipated by the LED is converted to light.

Total power dissipated = 5 × 2.5 = 12.5 Watts

  • Work done = power × time (in seconds)

Work done = 12.5 × (1 × 3600 + 15 × 60)

Work done = 56250 J = 56.25 kJ

Therefore, the power dissipated by the LED is 20 Watts and the work done for 1 hour 15 minutes is 56.25 kJ.

Learn more about electrical power and work done at: brainly.com/question/23901751

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3 0
2 years ago
A women who normally weighs 400 N stands on top of a ladder so high she is one full additional earth radius above the surface of
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The woman weighs 100N now.

Explanation:

Given:

F is given as 400N

one full additional earth radius formed

To Find:

Weight of the woman=?

Solution:

We know that gravitational force is inversely proportional to the square of radius.

f_g=\frac{1}{r^2}

where

f_g is the gravitational force

r^2 is the radius square

So when radius is doubled, the force becomes one fourth of the original.

Therefore \frac{1}{4} \times400 = 100N

3 0
3 years ago
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