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Scilla [17]
3 years ago
7

A women who normally weighs 400 N stands on top of a ladder so high she is one full additional earth radius above the surface of

the earth. How much does she weigh now
Physics
1 answer:
AveGali [126]3 years ago
3 0

The woman weighs 100N now.

Explanation:

Given:

F is given as 400N

one full additional earth radius formed

To Find:

Weight of the woman=?

Solution:

We know that gravitational force is inversely proportional to the square of radius.

f_g=\frac{1}{r^2}

where

f_g is the gravitational force

r^2 is the radius square

So when radius is doubled, the force becomes one fourth of the original.

Therefore \frac{1}{4} \times400 = 100N

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When the tube is filled with mercury vapor, as in this case, a sharp drop in the collected current is observed when the accelera
adell [148]

Answer:

4.9 eV .

Explanation:

It is the case of discharge through mercury tube light . In it , mercury  atoms are exited due to which electrons are sent to higher energy  level . Here current drops to zero because electrons are excited to higher level . Energy are absorbed in quantised manner . Energy absorbed by electrons will be 4.9 eV . That means , difference in energy  between two energy level is  4.9 eV .

3 0
3 years ago
How much force would a 55kg person experience on a roller coaster if they travel through a loop with a radius of 55kg at a speed
Inessa [10]

Answer:

200 N

Explanation:

For a body moving in uniform circular motion, the force acting on it will be <em>centripetal force</em> and its direction is <em>radially inward</em> , pointing to the center.

The radially inward acceleration, or the centripetal acceleration is given by :

                                          a = v² / r

           where v is the speed at which the body is moving and r is the radius of the circle

Given-

m = 55kg

v = 14.1 m/s

r= 55m

We know that F = ma

⇒   F = m (  v²/ r )

⇒ F = 55 x 14.1 x 14.1 / 55

⇒ F =14.1 x 14.1 = 200 N

∴ <em>The force acting is 200 N</em>.

5 0
3 years ago
If the star Sirius emits 23 times more energy than the Sun, why does the Sun appear brighter in the sky?
Ganezh [65]

Answer:

As b ∝ (L/r²) and

the distance of the sun from the earth is 0.00001581 light years

and

the distance of the Sirius from the earth is 8.6 light years

hence,

the Sun appear brighter in the sky

Explanation:

The brightness (b) is directly proportional to the Luminosity of the star (L) and inversely proportional to the square of the distance between the star and the observer (r).

thus, mathematically,

b ∝ (L/r²)

now,

given

L for sirius is 23 times more than the sun i.e 23L

now,

the distance of the sun from the earth is 0.00001581 light years

and

the distance of the Sirius from the earth is 8.6 light years

thus,

using the the relation between conclude that the value of brightness for the Sirius comes very very low as compared to the value for brightness for the Sun.

hence, the sun appears brighter

5 0
3 years ago
Kellie found a sample of a pure element. She carefully studied the sample and made a list of its properties.
aivan3 [116]
1. (C.) -Si- is silicone which at room temp is a solid and it's a hard crystalline Brittle rock basically...

2. And it will Be D. NOT C... i can't stand user's who throw out answers for free points.... 
3 0
3 years ago
A pulley system has an efficiency of 74.2%. If you perform 200 J of work, how
Fudgin [204]

Answer:

C

Explanation:

If a pulley system has an efficiency of 74.2%, then only that fraction of the work performed will be useful. 74.2%=0.742. 0.742*200 is about 148J. Hope this helps!

8 0
3 years ago
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