Answer
given,
speed of the vehicle = 130 Km/h
officers accelerates at = 12 km/h/s
time taken by the driver to catch the vehicle = ?
at time t second


t (12 t - 260 )= 0
12 t = 260
t = 21.67 s
v = u + at
v = 12 × 21.67
v = 260 Km/h
Answer:

Explanation:
We are given that

r=2 in when t=4 s
We have to find the rate of change of radius.
We know that
Volume of sphere=
Differentiate w.r.t t

Substitute the values



Speed = 11000 m/s = 11km/s
D = 380000 km,
t = D/s = 380000 km/ 11km/s
t = 34 545.45 seconds.
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Given Information:
diameter = d = 15 mm
Length = L = 20 mm
Axial load = P = 300 N
Eₚ = 2.70x10⁹ Pa
vₚ = 0.4
Required Information:
Change in length = ?
Change in diameter = ?
Answer:
Change in length = 0.01257 mm
Change in diameter = -0.003772 mm
Explanation:
Stress is given by
σ = P/A
Where P is axial load and A is the area of the cross-section
A = 0.25πd²
A = 0.25π(0.015)²
A = 0.000176 m²
σ = 300/0.000176
σ = 1697792.8 Pa
The longitudinal stress is given by
εlong = σ/Eₚ
εlong = 1697792.8/2.70x10⁹
εlong = 0.0006288 mm/mm
The change in length can be found by using
δ = εlong*L
δ = 0.0006288*20
δ = 0.01257 mm
The lateral stress is given by
εlat = -vₚ*εlong
εlat = -0.4*0.0006288
εlat = -0.0002515 mm/mm
The change in diameter can be found by using
Δd = εlat*d
Δd = -0.0002515*15
Δd = -0.003772 mm
Therefore, the change in length is 0.01257 mm and the change in diameter is -0.003772 mm