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Tema [17]
4 years ago
11

When a rock thrown straight up reaches its maximum height, its velocity is?

Physics
1 answer:
MakcuM [25]4 years ago
3 0
Using kinematic equation,
V² - U² = -2ah (minus g is in downward direction)
At highest point, final velocity will be zero. i.e V = 0.
∴ -U² = -2ah
U = √2gh (where a = g and h = maximum height achieved)

You can find velocity if h is given to you.

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a police officer parked on the side of the rode clockes a driver at a constant 130km/h (passing the stopped car). if the officer
nignag [31]

Answer

given,

speed of the vehicle = 130 Km/h

officers accelerates at = 12 km/h/s

time taken by the driver to catch the vehicle = ?

at time t second

130 t = \dfrac{1}{2}at^2

260 t - 12 t^2 = 0

t (12 t - 260 )= 0

12 t =  260

t = 21.67 s

v = u + at

v = 12 × 21.67

v = 260 Km/h

8 0
4 years ago
g You are blowing air into a spherical balloon at a rate of 33 cubic inches per second. Given that the radius of the balloon is
Marina CMI [18]

Answer:

\frac{3}{16\pi}in/sec

Explanation:

We are given that

\frac{dv}{dt}=3in^3/s

r=2 in when t=4 s

We have to find the rate of change of radius.

We know that

Volume of sphere=V=\frac{4}{3}\pi r^3

Differentiate w.r.t t

\frac{dV}{dt}=4\pi r^2\frac{dr}{dt}

Substitute the values

3=4\pi(2)^2\times \frac{dr}{dt}

\frac{dr}{dt}=\frac{3}{4\pi(2)^2}

\frac{dr}{dt}=\frac{3}{16\pi}in/sec

8 0
3 years ago
A rocket moves through outer space at 11,000 m/s. At this rate, how much time would be required to travel the distance from Eart
VladimirAG [237]
Speed = 11000 m/s = 11km/s

D = 380000 km,

t = D/s = 380000 km/ 11km/s

t = 34 545.45 seconds.
4 0
3 years ago
Define the following words:
qwelly [4]
Taxonomy: the techniques of describing,naming and classifying living organisms on the basis of similarities and dissimilarities

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7 0
3 years ago
The acrylic plastic rod is 20 mm long and 15 mm in diameter. If an axial load of 300 N is applied to it, determine the change in
Alecsey [184]

Given Information:  

diameter = d = 15 mm

Length = L = 20 mm

Axial load = P = 300 N

Eₚ = 2.70x10⁹ Pa

vₚ = 0.4

Required Information:  

Change in length = ?  

Change in diameter = ?  

Answer:  

Change in length = 0.01257 mm

Change in diameter = -0.003772 mm

Explanation:  

Stress is given by

σ = P/A

Where P is axial load and A is the area of the cross-section

A = 0.25πd²

A = 0.25π(0.015)²

A = 0.000176 m²

σ = 300/0.000176

σ = 1697792.8 Pa

The longitudinal stress is given by

εlong = σ/Eₚ

εlong = 1697792.8/2.70x10⁹

εlong = 0.0006288 mm/mm

The change in length can be found by using

δ = εlong*L

δ = 0.0006288*20

δ = 0.01257 mm

The lateral stress is given by

εlat = -vₚ*εlong

εlat = -0.4*0.0006288

εlat = -0.0002515 mm/mm

The change in diameter can be found by using

Δd = εlat*d

Δd = -0.0002515*15

Δd = -0.003772 mm

Therefore, the change in length is 0.01257 mm and the change in diameter is -0.003772 mm

7 0
3 years ago
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