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3 years ago

The separation between two magnets is reduced by a factor of 5. How does the force between them change?

Physics

1 answer:

gtnhenbr [62]3 years ago

7 0

Answer:Increase by a factor of 25

Explanation:

We know that magnetic force is proportional to $\frac{1}{r^2}$

where r is the distance between them

$F\propto B\propto \frac{1}{r^2}$

Thus $F\propto \frac{1}{r^2}$

Where $B$ =magnetic field

If distance is reduced by a factor of $5$ then force must increase by a factor of $25$ because

$r\rightarrow \frac{r}{5}$

so $F\propto \dfrac{1}{(\frac{r}{5})^2}$

$F\propto \frac{25}{r^2}$

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3 years ago

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2 years ago

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Given:

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Now, plug in the given values and solve for 'λ'. This gives,

$\lambda=\frac{3\times 10^8\ m/s}{9.38\times 10^{14}\ Hz}\\\\\lambda=3.2\times 10^{-7}\ m\\\\\lambda=3.2\times 10^{-7}\times 10^{6}\ \mu m\ [1\ m=10^6\ \mu m]\\\\\lambda=3.2\times 10^{-1}=0.32\ \mu m$

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3 years ago

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