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ehidna [41]
3 years ago
7

The thermal energy in a hot iron flows into a shirt. What can possibly be said about this situation?

Physics
1 answer:
lana [24]3 years ago
5 0
The iron is warmer than the shirt. Energy always flows to create equilibrium. And if the energy went from the iron to the shirt, we can conclude the shirt initially had less heat than the iron.
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Explanation:

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Given a force of 75N and an acceleration of 3m/s2, what is the mass
Ivahew [28]
<h2>mass = 25kg</h2><h2>---------------------------------</h2>

force = 75N --- (<em>g</em><em>i</em><em>v</em><em>e</em><em>n</em><em>)</em>

acceleration = 3m/s² ---- (<em>g</em><em>i</em><em>v</em><em>e</em><em>n</em><em>)</em>

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<h3>mass = 25kg</h3><h2>-----------------------------</h2><h2>FOLLOW ME</h2>
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3 years ago
What are the factors that influence the force of gravity
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A real (non-Carnot) heat engine, operating between heat reservoirs at temperatures of and performs 4.1 kJ of net work, and rejec
Sati [7]
There are some missing data in the problem. The full text is the following:
"<span>A </span>real<span> (</span>non-Carnot<span>) </span>heat engine<span>, </span>operating between heat reservoirs<span> at </span>temperatures<span> of 710 K and 270 K </span>performs 4.1 kJ<span> of </span>net work<span>, and </span>rejects<span> 9.7 </span>kJ<span> of </span>heat<span>, in a </span>single cycle<span>. The </span>thermal efficiency<span> of a </span>Carnot heat<span> engine, operating between the same </span>heat<span> reservoirs, in percent, is closest to.."

Solution:
The efficiency of a Carnot cycle working between cold temperature </span>T_C and  hot temperature T_H is given by
\eta = 1 - \frac{T_C}{T_H}
and it represents the maximum efficiency that can be reached by a machine operating between these temperatures. If we use the temperatures of the problem, T_C=270 K and T_H=710 K, the efficiency is
\eta = 1 - \frac{270 K}{710 K}=0.62 = 62%

Therefore, the correct answer is D) 62 %.
6 0
3 years ago
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