Answer:

Explanation:
Given that,
The compression in the spring, x = 0.0647 m
Speed of the object, v = 2.08 m/s
To find,
Angular frequency of the object.
Solution,
We know that the elation between the amplitude and the angular frequency in SHM is given by :

A is the amplitude
In case of spring the compression in the spring is equal to its amplitude



So, the angular frequency of the spring is 32.14 rad/s.
Answer:
24.57 revolutions
Explanation:
(a) If they do not slip on the pavement, then the angular acceleration is

(b) We can use the following equation of motion to find out the angle traveled by the wheel before coming to rest:

where v = 0 m/s is the final angular velocity of the wheel when it stops,
= 95rad/s is the initial angular velocity of the wheel,
is the deceleration of the wheel, and
is the angle swept in rad, which we care looking for:



As each revolution equals to 2π, the total revolution it makes before stop is
154.375 / 2π = 24.57 revolutions
1: only half the outlet is switched and the lamp is in the other half
2: the lamp is turned off.
3: The light bulb is burned out
4: the switch might be broken
5: the fuse might be blown
6: the electricity might be off