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IrinaK [193]
3 years ago
5

- What’s the median of 7 2 9 8 7 15 6 8

Mathematics
2 answers:
Mariana [72]3 years ago
8 0

answer is <em>7.5</em>

1 Order them from smallest to biggest

2 Cross them one by one from each side to find the middle number.

3 If there are two numbers like in this question you add them and divide by 2.

7+8= 15

15÷2=7.5

yaroslaw [1]3 years ago
6 0

Answer:

The answer is 7.5

Step-by-step explanation:

Put them in order of smallest to largest

2,6,7,7,8,8,9,15

Pick out the middle number

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You recently sent out a survey to determine if the percentage of adults who use social media has changed from 66%, which was the
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Answer:

The 98% confidence interval estimate of the proportion of adults who use social media is (0.56, 0.6034).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

Of the 2809 people who responded to survey, 1634 stated that they currently use social media.

This means that n = 2809, \pi = \frac{1634}{2809} = 0.5817

98% confidence level

So \alpha = 0.02, z is the value of Z that has a pvalue of 1 - \frac{0.02}{2} = 0.99, so Z = 2.327.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.5817 - 2.327\sqrt{\frac{0.5817*4183}{2809}} = 0.56

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.5817 + 2.327\sqrt{\frac{0.5817*4183}{2809}} = 0.6034

The 98% confidence interval estimate of the proportion of adults who use social media is (0.56, 0.6034).

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2 years ago
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Answer: zaria only had 20000 more that jessie in liters

Step-by-step explanation:

200 mill would be 20000

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