2 years ago

I need help with this

Physics

1 answer:

Angelina_Jolie [31]2 years ago

4 0

The answer would be 500 feet

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Cuales son las carreras de velocidad de medio fondo y fondo?

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Answer:

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Explanation:

58=8990

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5.3 × 1012 kg satellite is 1,800 m from another satellite that has a mass of 3.5 × 108 kg. What is the gravitational force betwe

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2 years ago

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A glass plate 2.25 mm thick, with an index of refraction of 1.80, is placed between a point source of light with wavelength 620

-BARSIC- [3]

Answer:

There are 2.71x10⁴ wavelengths between the source and the screen.

Explanation:

The number of wavelengths (N) can be calculated as follows:

$N = \frac{d_{g}}{\lambda_{g}} + \frac{d_{a}}{\lambda_{a}}$

Where:

$d_{g}$ : is the distance in glass = 2.25 mm

$d_{a}$ : is the distance in air = 1.50 cm - 0.225 cm = 1.275 cm

$\lambda_{g}$ : is the wavelength in glass

$\lambda_{a}$ : is the wavelength in air = 620 nm

To find the wavelength in glass we need to use the following equation:

$n_{g}*\lambda_{g} = n_{a}*\lambda_{a}$

Where:

$n_{g}$ : is the refraction index of glass = 1.80

$n_{a}$ : is the refraction index of air = 1

$\lambda_{g} = \frac{\lambda_{a}}{n_{g}} = \frac{620 nm}{1.80} = 344.4 nm$

Hence, the number of wavelengths is:

$N = \frac{d_{g}}{\lambda_{g}} + \frac{d_{a}}{\lambda_{a}}$

$N = \frac{2.25 \cdot 10^{-3} m}{344.4 \cdot 10^{-9} m} + \frac{1.275 \cdot 10^{-2} m}{620 \cdot 10^{-9} m}$

$N = 2.71 \cdot 10^{4}$

Therefore, there are 2.71x10⁴ wavelengths between the source and the screen.

I hope it helps you!

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2 years ago

The average mean distance of Earth from the sun is ____.

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Answer:

The mean distance of Earth from the Sun is 149.6 × 10^6 km and the mean distance of Mercury from the Sun is 57.9 × 10^6 km.

hope it helps you

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3 years ago

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