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liq [111]
3 years ago
8

rce versus time during the collision of a 44- tennis ball with a wall. The initial velocity of the ball is 36 perpendicular to t

he wall; it rebounds with the same speed, also perpendicular to the wall. What is the maximum value of the contact force during the collision

Physics
1 answer:
Sauron [17]3 years ago
3 0

Answer:

Maximum contact force = 487.4 N

Explanation:

The graph showing force vs time is attached to the solution of this question.

According to the an interpretation of Newton's second law of motion, the magmitude of the change in momentum is equal to the magnitude of the impulse experienced duting this impact.

F.t = Δ(momemtum)

Δ(momemtum) = 0.044 [36 - (-36)] = 0.044 × 72 = 3.168 kgm/s

Meaning, Impulse = 3.168 kgm/s too.

The area under the curve above is the impulse we just obtained.

If the maximum contact force is called F

The impulse = Area under this graph

= (1/2)(F)(4-0) + (F)(7-4) + (1/2)(F)(10-7)

= 2F + 3F + 1.5F = (6.5F) mN.s = (0.0065F) N.s

0.0065F = 3.168

F = (3.168/0.0065) = 487.4 N

Hope this Helps!!!

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What are the largest and smallest resistances you can obtain by connecting a 36.0-Ω , a 50.0-Ω , and a 700-Ω resistor together?
myrzilka [38]
<h2>Answer:</h2>

786Ω and 20.32Ω respectively.

<h2>Explanation:</h2>

(a) Given a number of resistors each with its own resistance, the largest resistance can be obtained when these resistors are connected in series.

From the question, the resistors have the following resistances;

36.0-Ω, 50.0-Ω , and 700-Ω

Now, when they are connected in series, the total resistance (R) obtainable is given by the sum of these individual resistances as follows;

R = 36.0-Ω + 50.0-Ω + 700-Ω

R = 786Ω

Therefore, the largest resistance that can be obtained by connecting  a 36.0-Ω , a 50.0-Ω , and a 700-Ω resistor together is 786Ω

(b) Similarly, given a number of resistors each with its own resistance, the smallest resistance can be obtained when these resistors are connected in parallel.

From the question, the resistors have the following resistances;

36.0-Ω, 50.0-Ω , and 700-Ω

Now, when they are connected in parallel, the total resistance (R) obtainable is given by using the relation as follows;

\frac{1}{R} = \frac{1}{36.0} + \frac{1}{50.0} + \frac{1}{700.0}

\frac{1}{R} = \frac{35000+25200+1800}{1260000}

\frac{1}{R} = \frac{62000}{1260000}

\frac{1}{R} = \frac{62}{1260}

R = \frac{1260}{62}

R = 20.32Ω

Therefore, the smallest resistance that can be obtained by connecting  a 36.0-Ω , a 50.0-Ω , and a 700-Ω resistor together is 20.32Ω

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Answer:

Both A and B

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Answer:

A.The positive z-direction

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Answer is b hope this helps
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