What are the types of magnet

Physics

1 answer:

KengaRu [80]2 years ago

4 0

Answer: pls mark me as a brainliest friend pls, it would be great help for me

Explanation: There are three types of magnets: permanent magnets, temporary magnets, and electromagnets. Permanent magnets emit a magnetic field without the need for any external source of magnetism or electrical power.

Hope it’s useful friend…

Good luck and have a great day buddy…

Stay safe and happy..

Keep rocking !!!

You might be interested in

A 65kg person throw a 0.045kg snowball forward with a ground speed of 30m/s. A second person, with a mass of 60kg, catches the s

Kobotan [32]

Well, st first we should find initial momentum for the first person represented in the task which definitely must be :
 $(65+0.045)*2.5$
And then we find the final one : $65*x + 0.045*30$
Then equate them together : $x=2.48 m/s$
So we can get the velocity, which is $is 2.48 m/s$
In that way, according to the main rules of conservation of momentum you can easily find the solution for the second person.
Regards!

6 0

3 years ago

A concert loudspeaker suspended high off the ground emits 28.0 W of sound power. A small microphone with a 0.700 cm2 area is 55.

grandymaker [24]

Explanation:

It is known that wave intensity is the power to area ratio.

Mathematically, I = $\frac{P}{A}$

As it is given that power is 28.0 W and area is $7 \times 10^{-5} m^{2}$ .

Therefore, sound intensity will be calculated as follows.

I = $\frac{P}{A}$

= $\frac{28.0 W}{4 \times 3.14 \times 7 \times 10^{-5} m^{2}}$

= $0.318 \times 10^{5} W/m^{2}$

or, = $3.18 \times 10^{4} W/m^{2}$

Thus, we can conclude that sound intensity at the position of the microphone is $3.18 \times 10^{4} W/m^{2}$ .

7 0

3 years ago

Which wave has a disturbance that is parallel to the wave motion?

Leto [7]

The answer is D.longitudinal

6 0

3 years ago

Step 2: Apply NEwton's second law Apply ∑Fy = may , what should ay be equal to, since the block doesn't move in the y direction

andrey2020 [161]

Answer:

∑Fy = 0, because there is no movement, N = m*g*cos (omega)

Explanation:

We can solve this problem with the help of a free body diagram where we show the respective forces in each one of the axes, y & x. The free-body diagram and the equations are in the image attached.

If the product of mass by acceleration is zero, we must clear the normal force of the equation obtained. The acceleration is equal to zero because there is no movement on the Y-axis.