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FromTheMoon [43]
3 years ago
10

The vertex formation of a parabola is x = 8(y- 1)2-76.

Mathematics
2 answers:
LiRa [457]3 years ago
8 0
The answer to this question is x = 8y^2 - 16y -68
Gennadij [26K]3 years ago
6 0

Answer:

\boxed{x=8y^2-16y-68}

Step-by-step explanation:

Hello, please consider the following.

x=8(y- 1)^2-76\\\\x=8(y^2-2y+1)-76\\\\x=8y^2-16y+8-76\\\\\boxed{x=8y^2-16y-68}

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

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just olya [345]
I’m confused as to what the question is? if knew the question i could potentially help.
5 0
2 years ago
Please help me
morpeh [17]

Answer:

No, because the cone has a smaller volume than the ice cream

Step-by-step explanation:

V=4

3πr3=4

3·π·33≈113.09734

Volume of scoop: 113.1 cm^2

V=πr2h

3=π·2.52·10

3≈65.44985

Volume of cone: 65.45 cm^2

65.45 < 113.1

6 0
3 years ago
Which values of k are solutions to the inequality StartAbsoluteValue negative k minus 2 EndAbsoluteValue less-than 18? Check all
Stella [2.4K]

Answer:

You could just replace all the given possible values of k in the inequality and see which ones are solutions, but let's solve this in a more interesting way:

First, remember how the absolute value works:

IxI = x if x ≥ 0

IxI = -x if x ≤ 0

Then if we have something like:

IxI < B

We can rewrite this as

-B < x < B

Now let's answer the question, here we have the inequality:

I-k -2I < 18

Then we can rewrite this as:

-18 < (-k - 2) < 18

Now let's isolate k:

first, we can add 2 in the 3 parts of the inequality:

-18 + 2 < -k - 2 + 2 < 18 + 2

-16 < -k < 20

Now we can multiply all sides by -1, remember that this also changes the direction of the signs, then:

-1*-16 > -1*-k > -1*20

16 > k > -20

Then k can be any value between these two limits.

So the correct options (from the given ones) are:

k = -16

k = -8

k = 0

6 0
3 years ago
Read 2 more answers
4x = -20 Solve for x
malfutka [58]

Answer:

x = -5

Step-by-step explanation:

x = -20/4 = -5

4 0
3 years ago
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According to a recent study, the carapace length for adult males of a certain species of tarantula are normally distributed with
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