1. Which of these has only one component?

A 50 mL beaker has an uncertainty of ± 10%. What is the absolute uncertainty for this beaker?

Pani-rosa [81]

Answer:

The absolute uncertainty is 10%.

Explanation:

The absolute uncertainty, sometimes referred to as absolute error, is the size of the possible range of values where by the actual or true value of a measurement probably lies.

The uncertainty of the 50 mL beaker is given as ± 10%. This implies that the volume recorded using the beaker will either be 10 % above or below the actual volume.

The absolute uncertainty ignores the direction of the error, whether above or below, and is mostly concerned with the magnitude of the error. We simply ignore the signs of the uncertainty and this will give the value of the absolute uncertainty.

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Fe2O3 + 3H2 → 2Fe + 3H20

Bingel [31]

Hope this helps
U can ask any doubt if u have

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What's a good model for isostasy is

lisov135 [29]

Is the water line of boat when someone boards or leaves it.

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A containing vessel holds a gaseous mixture of nitrogen and butane. Thepressure in the vessel at 126.9 Cis 3.0 atm. At 0 C, the

Viefleur [7K]

A vessel that contains a mixture of nitrogen and butane has a pressure of 3.0 atm at 126.9 °C and a pressure of 1.0 atm at 0 °C. The mole fraction of nitrogen in the mixture is 0.33.

A vessel contains a gaseous mixture of nitrogen and butane. At 126.9 °C (400.1 K) the pressure is due to the mixture is 3.0 atm.

We can calculate the total number of moles using the ideal gas equation.

$P \times V = n \times R \times T\\\\n = \frac{P \times V}{R \times T} = \frac{3.0 atm \times V}{0.082 atm.L/mol.K \times 400.1 K} = 0.091 mol/L \times V$

At 0 °C (273.15 K), the pressure due to the gaseous nitrogen is 1.0 atm.

We can calculate the moles of nitrogen using the ideal gas equation.

$P \times V = n \times R \times T\\\\n = \frac{P \times V}{R \times T} = \frac{1.0 atm \times V}{0.082 atm.L/mol.K \times 400.1 K} = 0.030 mol/L \times V$

The mole fraction of nitrogen in the mixture is:

$X(N_2) = \frac{0.030 mol/L \times V}{0.091 mol/L \times V} = 0.33$

A vessel that contains a mixture of nitrogen and butane has a pressure of 3.0 atm at 126.9 °C and a pressure of 1.0 atm at 0 °C. The mole fraction of nitrogen in the mixture is 0.33.

Learn more: brainly.com/question/2060778

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How a mineral's chemical make-up looks like?

sveticcg [70]

You would have to go to sephora and check it out

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