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3 years ago

What is the reasoning for the location of sodium in the periodic table

2 answers:

8 0

It is where it is because it goes in that group see reason that hydrogen is the first element grouped with some other gases because they are all related.

tatyana61 [14]3 years ago

3 0

Due to it's electronic configuration w/c is 1s2 2s2 2ps 3s1 considering the last w/c is 3s1, sodium should be in row 3 period a1.

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Assume that 8.5 L of iodine gas (I2) are produced at STP according to the following balanced equation:2KI(aq) + Cl2(

Aliun [14]

Answer: 0.3794 moles of Iodine gas are produced.

Explanation:

$2KI(aq)+Cl_2(
g)\rightarrow 2KCl(aq)+I_2$

Volume of iodine gas produced at STP =8.5 L

At STP, the 1 mol of gas occupies volume = 22.4 L

So, 8.5 L of volume will be occupied by: $\frac{1}{22.4 L}\times 8.5=0.3794 moles$

0.3794 moles of Iodine gas are produced.

5 0

3 years ago

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To Separate camphor from sand we use_______process.

Molodets [167]

Answer:

<h3><em>to Separate camphor from sand we use <u>sublimation</u> process.</em></h3><h3 /><h3 /><h3><em>Hope </em><em>it</em><em> </em><em>is </em><em>helpful</em><em> to</em><em> you</em><em> </em></h3>

3 0

2 years ago

PLEASE HELP

devlian [24]

Metals have a low electron affinity- a less likely chance to gain electrons because they want to give up their valence electrons rather than gain electrons, which require more energy than necessary.

6 0

2 years ago

Which formula represents a hydrocarbon with a double covalent bond?

Nataliya [291]

Answer:

c is the answer

step by step explanation is not

4 0

2 years ago

Part a use these data to calculate the heat of hydrogenation of buta-1,3-diene to butane. c4h6(g)+2h2(g)→c4h10(g)

Reptile [31]

<u>Answer:</u> The heat of hydrogenation of the reaction is coming out to be 234.2 kJ.

<u>Explanation:</u>

Enthalpy change is defined as the difference in enthalpies of all the product and the reactants each multiplied with their respective number of moles. It is represented as $\Delta H$

The equation used to calculate enthalpy change is of a reaction is:

$\Delta H_{rxn}=\sum [n\times \Delta H_{(product)}]-\sum [n\times \Delta H_{(reactant)}]$

For the given chemical reaction:

$C_4H_6(g)+2H_2(g)\rightarrow C_4H_{10}(g)$

The equation for the enthalpy change of the above reaction is:

$\Delta H_{rxn}=[(1\times \Delta H_{(C_4H_{10})})]-[(1\times \Delta H_{(C_4H_6)})+(2\times \Delta H_{(H_2)})]$

We are given:

$\Delta H_{(C_4H_{10})}=-2877.6kJ/mol\\\Delta H_{(C_4H_6)}=-2540.2kJ/mol\\\Delta H_{(H_2)}=-285.8kJ/mol$

Putting values in above equation, we get:

$\Delta H_{rxn}=[(1\times (-2877.6))]-[(1\times (-2540.2))+(2\times (-285.8))]\\\\\Delta H_{rxn}=234.2J$

Hence, the heat of hydrogenation of the reaction is coming out to be 234.2 kJ.

4 0

3 years ago