First compute the number of grams of manganese metal required to make 21.7 grams of H2.
21.7 g H2 x (1 mole H2/ 2 g H2) x (1 mole Mn/1 mol H2) x (55 grams Mn/1 mol Mn) = 596.75 grams
Now density = mass/volume
7.43 = 596.75/volume
volume = 596.75/7.43 = 80.31 mL
80.31 mL is the amount of manganese needed.
Yes. it was less clay which causes less area for impact
Info: NACl2<span> might be an improperly capitalized: </span>NaCl2<span>. Balanced equation: NA + Cl2 = </span>NACl<span>2. </span>Reaction type<span>: synthesis. Please tell about this free chemistry ...</span>
Answer:
'Oxidation states have changed.'
Explanation:
Redox Reactions can be identifiable by a change in oxidation number/states of two of the atoms in the reaction. Any reaction in which no oxidation numbers/state change is not a redox reaction.
1.9 mol H2.
3.8 mol HCl * (1 mol H2 / 2 mol HCl) = 1.9 mol H2