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tia_tia [17]
3 years ago
11

PLEASE HELP!!!!!!!))

Chemistry
2 answers:
evablogger [386]3 years ago
7 0
Ithe answer is 02 please it’s negative
Vedmedyk [2.9K]3 years ago
6 0
No e e jd si u shl use
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Roman55 [17]
0.5 mole of Mg=12 grams= 0.5x atoms
5 0
3 years ago
Iron is found in Earth's crust as several iron compounds. Calculate the mass in kilograms of the amount of each of the following
notka56 [123]

The mass of hematite that contains 8.0×10³ kg of iron is 2.29 × 10⁴ kg.

<h3>What are iron ores?</h3>

Iron ores refers to minerals in which iron occur in combined form found in the earth's crust.

Some ores of iron include:

  • hematite,
  • magnetite,
  • limonite, and
  • siderite.

Molar mass of hematite, Fe₂O₃ = 160 g/mol

Molar mass iron = 56 g/mol

Percent mass of iron in hematite = 56/160 = 35%

The mass of hematite that contains 8.0×10³ kg of iron = 8.0 × 10³kg/0.35 = 2.29 × 10⁴ kg.

Therefore, the mass of hematite that contains 8.0×10³ kg of iron is 2.29 × 10⁴ kg.

Learn more about iron ores at: brainly.com/question/4693242

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3 0
2 years ago
Catalysts increase reaction rates by lowering the activation energy of a reaction.
Setler [38]
The answer is true, catalysts increase rates by lowering the activation energy of a reaction. Catalysts lower the reaction energy and so the reaction occurs faster. Enzymes perform the role of biological catalysts. Most metabolic pathways of the body are controlled by enzymes. Enzymes by classification are proteins. <span />
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3 years ago
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A student is given an antacid tablet that weighs 5.4630 g. The tablet is crushed and 4.3620 g of the antacid is added to 200. mL
Luda [366]

Solution :

It is given that :

Weight of the antacid tablet = 5.4630 g

4.3620 gram of antacid is crushed and is added to the stomach acid of 200 mL and is reacted.

25 mL of the stomach acid that is partially neutralized required 13.6 mL of NaOH to be titrated for a red end point.

27.7 mL of $NaOH$ solution is equivalent to $25 \ mL$ of the original stomach acid. Therefore, 13.6 mL of NaOH will take x $\frac{25\text{ mL of original stomach acid}}{\text{27.7 mL of NaOH}}$

                                                             = 12.27 ml of the original stomach acid.

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3 years ago
Pls help 6th grade science
Eduardwww [97]
It’s A because it running more faster the the zebra
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