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Svetllana [295]
3 years ago
6

Given the following reaction:

Chemistry
1 answer:
Wewaii [24]3 years ago
3 0

Answer:

Approx. 4⋅g.

Explanation:

Moles of sulfuric acid =10.0⋅g98.08⋅g⋅mol−1=0.102⋅mol.

Now we have the molar quantity of sulfuric acid that react; we also have the stoichiometric equation that shows the molar equivalence of sulfuric acid, and lithium hydroxide.

Given the stoichiometry,

mass of water =0.102⋅mol×2×18.01.g.mol−1=??⋅g.

Why did I multiply the mass in this equation by 2? Am I pulling your leg?

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What is the ph of a solution labeled .30 trimethylamine k for trimethylamine is 7.42 x 10^4
valentina_108 [34]

Answer:the pH is 12

Explanation:

First We need to understand the structure of trimethylamine

Due to the grades of the bond in the nitrogen with a hybridization sp3 is 108° approximately, then is generated a dipole magnetic at the upper side of the nitrogen, this dipole magnetic going to attract a hydrogen molecule of the water making the water more alkaline

C3H9N+ H2O --> C3H9NH + OH-

k=\frac{[C3H9NH]*[OH-]}{[C3H9N]}

Then:

The concentration of the trimethylamine is 0.3 and the concentration of the ion C3H9NH is equal to the OH- relying on the stoichiometric equation. We could find the concentration of the OH- ion with the square root of the multiplication between k and the concentration of trimethylamine

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[OH-]=0.01

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4 years ago
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