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Lostsunrise [7]
2 years ago
15

Why do we use commas after transition words?

Chemistry
1 answer:
ra1l [238]2 years ago
8 0

Answer:

C - commas indicate a natural pause in the sentence

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An ultraviolet ray of light has a wavelength of 1.5x10^-8 m. What is the ray's<br> frequency?
frutty [35]

Answer:

2 E16 Hz    or     2 * 10^16 Hz

Explanation:

The formula to determine frequency is f = c / λ.

f = frequency

c = speed of light

λ = wavelength

f = 3E8 / 1.5E-8

f = 2E16

This makes sense because UV light exists roughly

between 8E14 Hz and 3E16 Hz ----- 2E16 Hz falls in that range

8 0
3 years ago
Sodium carbonate (NaCO3) is sometimes used as a water-softening agent. Suppose that a worker prepares a 0.730 M solution of NaCO
elena55 [62]

Answer : The mass of solute in solution is 1.09\times 10^2g.

Solution : Given,

Molarity = 0.730 M

Volume of solution = 1.421 L

Molar mass of sodium carbonate = 105.98 g/mole

Formula used for Molarity :

Molarity=\frac{w}{M\times V}

where,

w = mass of solute

M = Molar mass of solute

V = volume of solution in liter

Sodium carbonate is solute and water is solvent.

Now put the given values in above formula, we get the mass of solute in solution.

0.730mole/L=\frac{w}{(105.98g/mole)\times (1.412L)}

By rearranging the terms, we get

m=109.247g=1.09\times 10^2g

Therefore, the mass of solute in solution is 1.09\times 10^2g.

4 0
3 years ago
How many helium atoms are there in a helium blimp containing 539kg of helium
MaRussiya [10]
Atomic mass of helium is 4.002642g/mol 
(542000g)/(4.002642g/mol)*6.02*10^23 = 8.15*10^28 atoms
3 0
3 years ago
Read 2 more answers
How is kinetic energy related to solid?
Basile [38]

Answer:

because it is type of tht a solid

8 0
3 years ago
Read 2 more answers
Combustion analysis of a hydrocarbon produced 33.01 g co2 and 13.52 g h2o. calculate the empirical formula of the hydrocarbon.
Akimi4 [234]
Answer is: <span>the empirical formula of the hydrocarbon is CH</span>₂.<span>
Chemical reaction: C</span>ₓHₐ + O₂ → xC + a/2H₂O.<span>
m(CO</span>₂) = 33.01 g.
n(CO₂) = m(CO₂) ÷ M(CO₂).
n(CO₂) = 33.01 g ÷ 44.01 g/mol.
n(CO₂) = n(C) = 0.75 mol.
m(H₂O) = 13.52 g.
n(H₂O) = 13.52 g ÷ 18 g/mol.
n(H₂O) = 0.75 mol.
n(H) = 2 · n(H₂O) = 1.5 mol.
n(C) : n(H) = 0.75 mol : 1.5 mol /0.75 mol.
n(C) : n(H) = 1 : 2.

6 0
4 years ago
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