Which values of x are point(s) of discontinuity for this function? Please explain how you did it.
2 answers:
<span>The correct answers are:
x = 0
x = 2
Explanation:
When x < 0, the value of y = -</span>
<span>.
When x > 0, the value of y = </span><span>.
When x = 0, there is no value of y mentioned in the conditions; it means that there is discontinuity at x = 0.
When x < 2, the value of y = </span><span>.
When x >= 2, the value of y = 2.
It means that, at x = 2, there is a discontinuity because the graph of y = </span> is not touching the graph of y = 2 at x = 2.
x = 0
x = 2
Explanation:
When x < 0, the value of y = -</span>
When x > 0, the value of y = </span>
When x = 0, there is no value of y mentioned in the conditions; it means that there is discontinuity at x = 0.
When x < 2, the value of y = </span>
When x >= 2, the value of y = 2.
It means that, at x = 2, there is a discontinuity because the graph of y = </span>
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Answer:
Step-by-step explanation:
We are given parallelogram
Since, two opposite sides of any parallelogram are always equal
Let's assume first side =a
second side =b
so, we get
now, we can find perimeter
perimeter=2a+2b
so, we get
we can simplify it
................Answer