Question

Which values of x are point(s) of discontinuity for this function? Please explain how you did it.

Answer 1

Answer:SAME AS ABOVE

Step-by-step explanation:

Answer 2

The correct answers are:
x = 0
x = 2

Explanation:
When x < 0, the value of y = -$x^2$.
When x > 0, the value of y = $x^2$.
When x = 0, there is no value of y mentioned in the conditions; it means that there is discontinuity at x = 0.

When x < 2, the value of y = $x^2$.
When x >= 2, the value of y = 2.

It means that, at x = 2, there is a discontinuity because the graph of y = $x^2$ is not touching the graph of y = 2 at x = 2.