What is the value of tangent theta in the unit circle below? One-half StartFraction StartRoot 3 EndRoot Over 3 EndFraction Start
2 answers:
Answer:
Step-by-step explanation:
A unit circle is defined as a circle of unit radius (that is the radius of the circle is equal to 1). In trigonometry, the unit circle is a circle with a radius of 1, while centered at the origin (0, 0) in the Cartesian coordinate.
In the unit circle below, we can see that the line touches the unit circle at point , therefore to find the tangent of theta, we use the formula:
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Answer:
- ABCD is a rhombus, and a parallelogram
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<h3>Given </h3>- Points A(-6, - 1), B(4, - 6), C(2, 5), D(- 8, 10)
First, plot the points (see attached picture).
Then, connect all the points.
<h3>We see that:</h3>- Opposite sides are parallel,
- Diagonals are perpendicular.
From our observation the figure is rhombus.
Let's confirm it with the following.
1) Find midpoints of diagonals and compare.
- AC → x = (- 6 + 2)/2 = - 2, y = (- 1 + 5)/2 = 2
- BD → x = (4 - 8)/2 = - 2, y = (- 6 + 10)/2 = 2
The midpoint of both diagonals is same (- 2, 2).
2) Find slopes of diagonals and check if their product is -1, this will confirm they are perpendicular.
- m(AC) = (5 - (-1))/(2 - (-6)) = 6/8 = 3/4
- m(BD) = (10 - (-6))/(-8 - 4) = - 16/12 = - 4/3
- m(AC) × m(BD) = 3/4 * (- 4/3) = - 1
<u>Confirmed.</u>
So this is a rhombus and also a parallelogram but <u>not</u> rectangle or square, since opposite angles are not right angles.
