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defon
3 years ago
7

Square root of x plus 9 − 4 = 1

Mathematics
2 answers:
Sergeeva-Olga [200]3 years ago
8 0

Answer:

drrrrrrrrrrrrrrrrrrrrrrrrrrr

Step-by-step explanation:

kari74 [83]3 years ago
8 0
X = 16, solution is extraneous
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(*+15)&lt;==(8<br> 5 9<br> 9<br> x +15 &lt;7-8-X<br> 3 10<br> 2
Diano4ka-milaya [45]

Answer:

which class question is this

6 0
3 years ago
Evaluate the numericial expression (32 - 20) ÷ 4
SashulF [63]

Answer:

3

Step-by-step explanation:

(32-20)÷4

solve perentisis first

(12)÷4

now divide

=3

3 0
3 years ago
Read 2 more answers
Can anyone find the answer????
avanturin [10]

Answer:

A≈351.86 or rounded to the nearest tenth, 351.9.

6 0
4 years ago
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What is 50+15d=125 equivalent to
zlopas [31]

Step-by-step explanation:

50-50+15d =125-50

15d = 75

15d/15=75/15

d=5

7 0
4 years ago
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A manufacturer produces piston rings for an automobile engine. It is known that ring diameter is normally distributed with σ=0.0
oksian1 [2.3K]
<h2>Answer with explanation:</h2>

The confidence interval for population mean is given by :-

\overline{x}\pm z^* SE                   (1)

, where \overline{x} = sample mean

z* = critical value.

SE = standard error

and SE=\dfrac{\sigma}{\sqrt{n}} , \sigma = population standard deviation.

n= sample size.

As per given , we have

\overline{x}=74.021

\sigma=0.001

n= 15

It is known that ring diameter is normally distributed.

SE=\dfrac{0.001}{\sqrt{15}}=0.000258198889747\approx0.000258199

By z-table ,

The critical value for 95% confidence  = z*= 1.96

A 99% two-sided confidence interval on the true mean piston diameter :

74.021\pm (2.576) (0.000258199)     (using (1))

74.021\pm 0.000665120624

74.021\pm 0.000665120624\\\\=(74.021- 0.000665120624,\ 74.021+ 0.000665120624)\\\\=(74.0203348794,\ 74.0216651206)\approx(74.020,\ 74.022)  [Rounded to three decimal places]

∴  A 99% two-sided confidence interval on the true mean piston diameter  = (74.020, 74.022)

By z-table ,

The critical value for 95% confidence  = z*= 1.96

A 95% lower confidence bound on the true mean piston diameter:

74.021- (1.96) (0.000258199)    (using (1))

74.021- 0.00050607004=74.02049393\approx74.020 [Rounded to three decimal places]

∴  A 95% lower confidence bound on the true mean piston diameter= 74.020

7 0
3 years ago
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