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Diano4ka-milaya [45]
3 years ago
14

Find the value of x. Then find the measure of each labeled angle.

Mathematics
1 answer:
adell [148]3 years ago
4 0

Answer:

x = 111

Step-by-step explanation:

x + x - 42  = 180     {Lines are parallel. So, they are supplementary}

2x - 42 = 180  

Add 42 to both sides

2x - 42 + 42 = 180 + 42

               2x = 222          {Divide both sides by 2}

                 x = 222/2

x = 111

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2. A snail weighed s ounces. One day the snail drank 5 times its weight in water and ate half its weight in food. Which equation
anastassius [24]

Answer:

Option D : t = 5s + s/2 is the correct answer.

Step-by-step explanation:

Given that:

t = Combined weight of water and food

s = weight of the snail

Water drank by snail = 5s

Food ate by snail = s/2

Combined weight = Weight of water + Food

t = 5s + s/2

Hence,

Option D : t = 5s + s/2 is the correct answer.

4 0
3 years ago
Need help? Sorry if u see my work that I erased
sveta [45]
6
4
4
12
3
4
I can't read the last one, sorry.
8 0
3 years ago
Read 2 more answers
the endpoints of the diameter of a circle are (−6, 6) and (6, −2), what is the standard form equation of the circle?
miss Akunina [59]
The equation of a circle in standard form is

(x - h)^2 + (y - k)^2 = r^2

where (h, k) is the center of the circle, and r is the radius if the circle.

We need to find the radius and center of the circle.
We are given a diameter, so to find the center, we need the midpoint of the diameter.

M = ((-6 + 6)/2, (6 + (-2))/2) = (0, 2)
The center is (0, 2).

To find the radius, we find the length of the given diameter and divided by 2.

d = \sqrt{(-6 - 6)^2 + (6 - (-2))^2)}

d = \sqrt{144 + 64}

d = \sqrt{208}

r = \dfrac{d}{2} = \dfrac{\sqrt{208}}{2} = \dfrac{\sqrt{208}}{\sqrt{4}} = \sqrt{52}

(x - 0)^2 + (y - 2)^2 = (\sqrt{52})^2

x^2 + (y - 2)^2 = 52
7 0
3 years ago
A player plays a game in which, during each round, he has a probability 0.55 of winning $1 and probability 0.45 of losing $1. Th
Artemon [7]

Answer:

45

Step-by-step explanation:

4 0
3 years ago
Suppose that each observation in a random sample of 100 fatal bicycle accidents in 2015 was classified according to the day of t
liraira [26]

Answer:

The calculated χ² =  0.57   does not fall in the critical region χ² ≥  12.59  so we fail to reject the null hypothesis and conclude the proportion of fatal bicycle accidents in 2015 was the same for all days of the week.

Step-by-step explanation:

1) We set up our null and alternative hypothesis as

H0:  proportion of fatal bicycle accidents in 2015 was the same for all days of the week

against the claim

Ha:  proportion of fatal bicycle accidents in 2015 was not the same for all days of the week

2) the significance level alpha is set at 0.05

3) the test statistic under H0 is

χ²= ∑ (ni - npi)²/ npi

which has an approximate chi square distribution with ( n-1)=7-1=  6 d.f

4) The critical region is χ² ≥ χ² (0.05)6 = 12.59

5) Calculations:

χ²= ∑ (16- 14.28)²/14.28 + (12- 14.28)²/14.28 + (12- 14.28)²/14.28 + (13- 14.28)²/14.28 + (14- 14.28)²/14.28 + (15- 14.28)²/14.28 + (18- 14.28)²/14.28

χ²= 1/14.28 [ 2.938+ 5.1984 +5.1984+1.6384+0.0784 +1.6384+13.84]

χ²= 1/14.28[8.1364]

χ²= 0.569= 0.57

6) Conclusion:

The calculated χ² =  0.57   does not fall in the critical region χ² ≥  12.59  so we fail to reject the null hypothesis and conclude the proportion of fatal bicycle accidents in 2015 was the same for all days of the week.

b.<u> It is r</u>easonable to conclude that the proportion of fatal bicycle accidents in 2015 was the same for all days of the week

6 0
3 years ago
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