-9/11 multiplied by -11/9

If two of a triangles angles measure 42 degrees and 48 degrees, how would you classify that triangle

grin007 [14]

I think that would be a right angle triangle or is that not what it is meaning

5 0

2 years ago

Read 2 more answers

Let the following sample of 8 observations be drawn from a normal population with unknown mean and standard deviation:

Vikentia [17]

Answer:

a

$\= x = 18.5$ , $\sigma = 5.15$

b

$15.505 < \mu < 21.495$

c

$14.93 < \mu < 22.069$

Step-by-step explanation:

From the question we are are told that

The sample data is 21, 14, 13, 24, 17, 22, 25, 12

The sample size is n = 8

Generally the ample mean is evaluated as

$\= x = \frac{\sum x }{n}$

$\= x = \frac{ 21 + 14 + 13 + 24 + 17 + 22+ 25 + 12 }{8}$

$\= x = 18.5$

Generally the standard deviation is mathematically evaluated as

$\sigma = \sqrt{\frac{\sum (x- \=x )^2}{n}}$

$\sigma = \sqrt{\frac{\sum ((21 - 18.5)^2 + (14-18.5)^2+ (13-18.5)^2+ (24-18.5)^2+ (17-18.5)^2+ (22-18.5)^2+ (25-18.5)^2+ (12 -18.5)^2 )}{8}}$

$\sigma = 5.15$

considering part b

Given that the confidence level is 90% then the significance level is evaluated as

$\alpha = 100-90$

$\alpha = 10\%$

$\alpha = 0.10$

Next we obtain the critical value of $\frac{ \alpha }{2}$ from the normal distribution table the value is

$Z_{\frac{ \alpha }{2} } = 1.645$

The margin of error is mathematically represented as

$E = Z_{\frac{ \alpha }{2} } * \frac{\sigma }{\sqrt{n} }$

=> $E =1.645 * \frac{5.15 }{\sqrt{8} }$

=> $E = 2.995$

The 90% confidence interval is evaluated as

$\= x - E < \mu < \= x + E$

substituting values

$18.5 - 2.995 < \mu < 18.5 + 2.995$

$15.505 < \mu < 21.495$

considering part c

Given that the confidence level is 95% then the significance level is evaluated as

$\alpha = 100-95$

$\alpha = 5\%$

$\alpha = 0.05$

Next we obtain the critical value of $\frac{ \alpha }{2}$ from the normal distribution table the value is

$Z_{\frac{ \alpha }{2} } = 1.96$

The margin of error is mathematically represented as

$E = Z_{\frac{ \alpha }{2} } * \frac{\sigma }{\sqrt{n} }$

=> $E =1.96 * \frac{5.15 }{\sqrt{8} }$

=> $E = 3.569$

The 95% confidence interval is evaluated as

$\= x - E < \mu < \= x + E$

substituting values

$18.5 - 3.569 < \mu < 18.5 + 3.569$

$14.93 < \mu < 22.069$

8 0

3 years ago

Miguel and three friends went to the movies. each boy spent 9.50 on a ticket and had the same amount of money leftover. They ori

Nataliya [291]

Answer:

$2.5

Step-by-step explanation:

4 people went to the movies and spent $ 38 ( 9.50* 4= 38) since 48-38 = 10

they totally have 10 dollars left. 10/4 = 2.5 They each $2.5 left

4 0

2 years ago

A random variable X follows the continuous uniform distribution with a lower bound of −4 and an upper bound of 18. a. What is th

shutvik [7]

Answer:

The height of the density function is $\frac{1}{22}$

Step-by-step explanation:

Given : A random variable X follows the continuous uniform distribution with a lower bound of −4 and an upper bound of 18.

To find : What is the height of the density function f(x)?

Solution :

According to question,

The height of the density function is given by,

$f(X)=\frac{1}{b-a}$

Where, a is the lower bound a=-4

b is the upper bound b=18

Substitute the value in the formula,

$f(X)=\frac{1}{18-(-4)}$

$f(X)=\frac{1}{18+4}$

$f(X)=\frac{1}{22}$

Therefore, The height of the density function is $\frac{1}{22}$

5 0

3 years ago

Read 2 more answers

K= y/x (3x-1)-2.75(x+2)

defon

Answer:

k=

−2.75x2+3xy−5.5x−y/x

Step-by-step explanation:

Hi! so i see you need help with this problem let me help you and guide you through the steps :]

Let's solve for k.

k= y/x

(3x−1)−2.75(x+2)

Step 1: Multiply both sides by x.

kx=−2.75x2+3xy−5.5x−y

Step 2: Divide both sides by x.

kx/x

=

−2.75x2+3xy−5.5x−y/x

k=

−2.75x2+3xy−5.5x−y/x

Answer:

k=

−2.75x2+3xy−5.5x−y/x

8 0

2 years ago