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tatuchka [14]
1 year ago
11

.................................

Mathematics
2 answers:
Dafna11 [192]1 year ago
7 0

Answer:

You have to solve these expressions according to the BODMAS theory.

That is,

B ⇒ Brackets

O ⇒ Of

D ⇒ Division

M ⇒ Multiplication

A ⇒ Addition

S ⇒ Subtraction

Let us verify the expressions now.

1) -5 × [ (-7) + (-5) ] = [ (-5) × (-7) ] + [ (-5) × (-5) ]

         -5 × [ -7 -5 ] = [ 35 ] + [ 25 ]

               -5 × -12 = 60

                      <u>60 = 60</u><em>  (verified)</em>

<u>                                                                </u>

2) ( -7 ) × [ (-8) + 9 ] = [ -7 × (-8) ] + [ (-7) × 9 ]

                     -7 × 1 = [ 56 ] - 63

                          <u> -7 = -7 </u><em>(verified)</em>

<u>                                                                  </u>

c) (-25) × [ (-7) + (-15) ] = [ (-25) × (-7) ] + [ (-25) × (-15)]

               -25 × [ -22 ] = 175 + 375

                         <u>  550 = 550  </u><em>(verified)</em>

pogonyaev1 year ago
5 0

      For all of these we will use the Order of Operations, also known as PEMDAS, then compare the simplifed values to see if they are equal.

      [a] Equivalent / Verified

(-5) * [(-7) + (-5)] = [(-5) * (-7)] + [(-5) * (-5)]

(-5) * [-12] = [35] + [25]

60 = 60

      [b] Equivalent / Verified

(-7) * [(-8) + 9] = [-7 * (-8)] + [(-7) * 9]

(-7) * [1] = [56] + [-63]

-7 = -7

      [c] Equivalent / Verified

(-25) * [(-7) + (-15)] = [(-25) * (-7)] + [(-25) * (-15)]

(-25) * [-22] = [175] + [375]

550 = 550

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Step-by-step explanation:

A can is cylindrical in nature and volume of a cylinder is expressed as;

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Since diameter = 2r

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Substituting the given parameters into the formula to get the height h will give;

20π = πr²h

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<em>Step-by-step explanation</em>

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\begin{gathered} 3x+2y=12\text{ \lparen eq. 1\rparen} \\ 5x-y=7\text{ \lparen eq. 2\rparen} \end{gathered}

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\begin{gathered} 3x+2y-2y=12-2y \\ 3x=12-2y \\ \frac{3x}{3}=\frac{12-2y}{3} \\ x=\frac{12}{3}-\frac{2}{3}y \\ x=4-\frac{2}{3}y\text{ \lparen eq. 3\rparen} \end{gathered}

Substituting equation 3 into equation 2 and solving for y:

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