Only selections B and D give a maximum height of 13 at t=3. However, both of those functions have the height be -5 at t=0, meaning the ball was served from 5 ft below ground. This does not seem like an appropriate model.

We suspect ...
• the "correct" answers are probably B and D
• whoever wrote the problem wasn't paying attention.

8 0

3 years ago

Read 2 more answers

If the area of a park is exactly halfway between 2.4 and 2.5 acres what is the area of the park

Paul [167]

Get the distance between two acres.

2.5 - 2.4 = 0.1

Divide the diffence by 2
0.1 / 2 = 0.05 - Halfway between them.

Therefore, 0.05 must be taken from 2.5 acres. it must be added to 2.4 acres to get the exact area of the park.

2.5 - 0.05 = 2.45
2.4 + 0.04 = 2.45 acres

OR

Simply get the average of the two to get the area since it is exactly halfway between the two acres of land.

2.5 + 2.4 = 2.9 / 2 = 2.45 acres

8 0

3 years ago

Read 2 more answers

Can someone please help me with number 26

Ipatiy [6.2K]

300 is the original amount and 0.5 is the rate (a percent) which is deacying because it is less than 1

5 0

3 years ago

Read 2 more answers

According to the US Bureau of labor statistics, 7% of US female workers between 16 and 24 years old are paid at the minimum wage

vladimir1956 [14]

Answer:

The Null Hypothesis is $H_o:k_o = 0.07$

The alternative hypothesis is $H_a :k_o \ne 0.07$

Decision rule

If the test staistics is greater than the critical value of significance level then $H_o$ is accepted else $H_o$ is rejected

With the above in mind

The critical value of the significance level which is obtained from the table is

$t_{0.05} = 1.645$

Now since the critical value of significance level is greater than the test staistics then the null hypothesis will be rejected

Conclusion

The information is not enough to back the claim that state differs from the nation

Step-by-step explanation:

From the question we are told that

The percentage of US female workers paid at the minimum wage or less is $k_o =$ 7% = 0.07

The sample size is $n = 500$

The number paid minimum wage or less is x = 42

The significance level is $\alpha =$ 5% = 0.05

Now the probability of getting a US female workers paid at the minimum wage or less is mathematically represented as

$\= k = \frac{x}{n}$

substituting value

$\= k = \frac{42}{500}$

$\= k = 0.084$

The Null Hypothesis is $H_o:k_o = 0.07$

The alternative hypothesis is $H_a :k_o \ne 0.07$

Generally the test statistics is mathematically evaluated as

$z = \frac{\= k - k_o}{\sqrt{\frac{k_o(1-k_o)}{n} } }$

substituting value

$z = \frac{0.084 - 0.07}{\sqrt{\frac{0.07 (1-0.07)}{500} } }$

$z = 1.23$

Now the Decision rule is stated as

If the test staistics is greater than the critical value of significance level then $H_o$ is accepted else $H_o$ is rejected

With the above in mind

The critical value of the significance level which is obtained from the table is

$t_{0.05} = 1.645$

Now since the critical value of significance level is greater than the test staistics then the null hypothesis will be rejected

So the conclusion will be

The information is not enough to back the claim that state differs from the nation

4 0

4 years ago