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2 years ago

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Almonds are a member of the peach family

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Alex777 [14]2 years ago

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What is the probability of rolling a number greater than 4 on a fair number cube (dice)? (Simplify to lowest terms)

Reptile [31]

Answer:

1/3

Step-by-step explanation:

there are 2 numbers greater than 4 on dice and there are 6 numbers on a die

3 0

3 years ago

(-2×0.7-1)÷-2<br><br> I got 1.2 but not sure if its right.

salantis [7]

Answer:

1.2

Step-by-step explanation:

First you multiply -2 and 0.7

Which is -1.4

-1.4-1 is

-2.4/-2

is 1.2

So you are correct the answer is

1.2

Good Job on getting it!

8 0

2 years ago

Read 2 more answers

What is the cube root of 27a^12

fiasKO [112]

Cube root of 27 a^12 will be: 3 a^4.

7 0

3 years ago

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I need to solve for a and b

Jlenok [28]

Answer:

Not sure Sorry i couldn't help

Step-by-step explanation:

5 0

3 years ago

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liraira [26]

For x such that 0 < x < $\frac{\pi}{2}$ , the mathematical expression is:

$\frac{\sqrt{1 \;-cos^2x} }{sinx} + \frac{\sqrt{1 \;-sin^2x} }{cosx} = 1+1=2$

<u>Given the following data:</u>

$\frac{\sqrt{1 \;-cos^2x} }{sinx}$

$\frac{\sqrt{1 \;-sin^2x} }{cosx}$

In Trigonometry, you should take note of the following mathematical expression:

$sin^2x + cos^2x = 1$

Therefore, we can obtain the following:

$sin^2x = 1 - cos^2x$ ...equation 1.

$cos^2x = 1 - sin^2x$ ...equation 2.

Substituting the equations respectively, we have:

$\frac{\sqrt{1 \;-cos^2x} }{sinx} + \frac{\sqrt{1 \;-sin^2x} }{cosx} = \frac{\sqrt{sin^2x} }{sinx} + \frac{\sqrt{cos^2x} }{cosx}\\\\$

Taking the square roots, we have:

$\frac{sinx}{sinx} + \frac{cosx}{cosx} = 1 +1\\\\1+1=2$

Therefore, for x such that 0 < x < $\frac{\pi}{2}$ , the expression is:

$\frac{\sqrt{1 \;-cos^2x} }{sinx} + \frac{\sqrt{1 \;-sin^2x} }{cosx} = 1+1=2$

Read more on trigonometry here: brainly.com/question/4515552

7 0

2 years ago

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