Answer:
<h2>Yes</h2>
Step-by-step explanation:
The formula of a distance between two points:
![d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}](https://tex.z-dn.net/?f=d%3D%5Csqrt%7B%28x_2-x_1%29%5E2%2B%28y_2-y_1%29%5E2%7D)
ΔABC:
A(2, 5), B(5, 5), C(5, 9)
![AB=\sqrt{(5-2)^2+(5-5)^2}=\sqrt{3^2+0^2}=\sqrt{9+0}=\sqrt9=3\\\\AC=\sqrt{(5-2)^2+(9-5)^2}=\sqrt{3^2+4^2}=\sqrt{9+16}=\sqrt{25}=5\\\\BC=\sqrt{(5-5)^2+(9-5)^2}=\sqrt{0^2+4^2}=\sqrt{0+16}=\sqrt{16}=4](https://tex.z-dn.net/?f=AB%3D%5Csqrt%7B%285-2%29%5E2%2B%285-5%29%5E2%7D%3D%5Csqrt%7B3%5E2%2B0%5E2%7D%3D%5Csqrt%7B9%2B0%7D%3D%5Csqrt9%3D3%5C%5C%5C%5CAC%3D%5Csqrt%7B%285-2%29%5E2%2B%289-5%29%5E2%7D%3D%5Csqrt%7B3%5E2%2B4%5E2%7D%3D%5Csqrt%7B9%2B16%7D%3D%5Csqrt%7B25%7D%3D5%5C%5C%5C%5CBC%3D%5Csqrt%7B%285-5%29%5E2%2B%289-5%29%5E2%7D%3D%5Csqrt%7B0%5E2%2B4%5E2%7D%3D%5Csqrt%7B0%2B16%7D%3D%5Csqrt%7B16%7D%3D4)
ΔDEF:
D(-7, 8), E(-4, 8), F(-4, 4)
![DE=\sqrt{-4-(-7))^2+(8-8)^2}=\sqrt{3^2+0^2}=\sqrt{9+0}=\sqrt9=3\\\\DF=\sqrt{(-4-(-7))^2+(4-8)^2}=\sqrt{3^2+(-4)^2}=\sqrt{9+16}=\sqrt{25}=5\\\\EF=\sqrt{(-4-(-4))^2+(4-8)^2}=\sqrt{0^2+(-4)^2}=\sqrt0+16}=\sqrt{16}=4](https://tex.z-dn.net/?f=DE%3D%5Csqrt%7B-4-%28-7%29%29%5E2%2B%288-8%29%5E2%7D%3D%5Csqrt%7B3%5E2%2B0%5E2%7D%3D%5Csqrt%7B9%2B0%7D%3D%5Csqrt9%3D3%5C%5C%5C%5CDF%3D%5Csqrt%7B%28-4-%28-7%29%29%5E2%2B%284-8%29%5E2%7D%3D%5Csqrt%7B3%5E2%2B%28-4%29%5E2%7D%3D%5Csqrt%7B9%2B16%7D%3D%5Csqrt%7B25%7D%3D5%5C%5C%5C%5CEF%3D%5Csqrt%7B%28-4-%28-4%29%29%5E2%2B%284-8%29%5E2%7D%3D%5Csqrt%7B0%5E2%2B%28-4%29%5E2%7D%3D%5Csqrt0%2B16%7D%3D%5Csqrt%7B16%7D%3D4)
AB ≅ DE
AC ≅ DF
BC ≅ EF
Therefore ΔABC ≅ ΔDEF
Answer:
x = 25 degrees.
Step-by-step explanation:
By the external angle of a triangle theorem x + <C = 50
But x = <C ( alternate angles).
Therefore 2x = 50
x = 25.