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3 years ago

A.Calculate the mean,median and mode.(3 points each) 1.)1,2,3,4,5 2.)2,3,4,5,6,6 3.)6,7,5,4,5,6,2,5

Mathematics

1 answer:

zlopas [31]3 years ago

5 0

Answer:

Step-by-step explanation:

1.)1,2,3,4,5

mean=sum of all values/number of values

=1+2+3+4+5/5

=15/5

mean=3

Mode :

In the given data, no observation occurs more than once.

Hence the mode of the observations does not exist, means mode=0.

Median

1,2,3,4,5

Middle value is 3 so the median is 3.

2.)2,3,4,5,6,6

mean=sum of all values/number of values

=2+3+4+5+6+6/6

=26/6

mean =4.33

Mode

is that value of the observation which occurs maximum number of times so here mode is 6.

Median

2,3,4,5,6,6

4+5/2

9/2

median=4.5

3.)6,7,5,4,5,6,2,5

mean=sum of all values/number of values

=6+7+5+4+5+6+2+5/8

=40/8

mean =5

Mode

is that value of the observation which occurs maximum number of times so here mode is 5

Median

2,4,5,5,5,6,6,7

5+5/2

10/2

median=5

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An object is launched vertically upward from a 25 foot platform and is modeled by the function s(t)=−16t2+11t+25.

ch4aika [34]

Correct option:

d. 1.64

<h2>Explanation:</h2>

An object is launched vertically upward from a 25 foot platform and is modeled by the following function:

$s(t)=-16t^2+11t+25$

So this is the equation of a parabola because the object is a projectile so it follows the Projectile Motion.

The object fall back to the ground when $s(t)=0$ so:

$-16t^2+11t+25=0 \\ \\ \\ Using \ quadratic \ formula: \\ \\ t_{12}=\frac{-b\pm \sqrt{b^2-4ac}}{2a} \\ \\ a=-16 \\ \\ b=11 \\ \\ c=25 \\ \\ \\ t_{12}=\frac{-11\pm \sqrt{11^2-4(-16)(25)}}{2(-16)} \\ \\ t_{12}=\frac{-11\pm 41.48}{-32} \\ \\ t_{1}=\frac{-11+ 41.48}{-32}=-0.95s \\ \\ t_{2}=\frac{-11- 41.48}{-32}=1.64s$