Answer:
The Volume of large cone is 19.545 
greater than the smaller cone
Step-by-step explanation:
Given:
Size of the small cone = 3.5 inches
Diameter of the small cone = 3 inches
Size of the large cone = 3.5 inches
Diameter of the small cone = 3 inches
To Find:
How much greater, to the nearest tenth of a cubic inch, is the volume of the larger cone than the volume of the smaller cone = ?
Solution:
Volume of the small cone :
Radius = 
Radius = 
Radius = 1.5 inches
volume of the cone =
substituting the values,
=>
=>
=> 16.485
Volume of the large cone :
Volume of the large cone :
Radius =
Radius = 
Radius = 2.25 inches
volume of the cone =
substituting the values,
=>
=>
=>36.06
Now ,
volume of small cone - volume of large cone
=>36.06 - 16.485
=>19.545
92 dollars because 20 percent is 23 dollars so the answer is 92 dollars
∛(-45) = ∛((-1) × 45) = ∛(-1) × ∛45 = -∛45
Similarly,
∛(-101) = - ∛101
Now,
• 3³ = 27 and 4³ = 64, and 27 < 46 < 64, so ∛27 < ∛45 < ∛64, which places ∛45 between 3 and 4
• 5³ = 125, so ∛101 would similarly fall between 4 and 5
So to summarize, we have
3 < ∛45 < 4 < ∛101 < 5
so that
-5 < ∛(-45) < -4 < ∛(-101) < -3
so the integer between these numbers is -4.
Step-by-step explanation:
⇒12)It is an arithmetic sequence.
d=2-1=3-2=4-3=1
a(n) = a +(n-1)d
a(n) = 1+(n-1)1
The next three terms:
a(6) = 1+(6-1)1=6
a(7) = 1+(7-1)1=7
a(8) = 1+(8-1)1=8
⇒13)It is an arithmetic sequence.
d=0-3=-3-0=-6+3=-3
a(n) = a +(n-1)d
a(n) = 3+(n-1)-3
The next three terms:
a(5) = 3+(5-1)-3=-9
a(6) = 3+(6-1)-3=-12
a(7) = 3+(7-1)-3=-15
⇒14)It is <u>not </u>an arithmetic sequence.
⇒15) a(50) = 10 +(50-1)5
=<u>255</u>
<u>I hope this helps</u>
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