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Marat540 [252]
2 years ago
13

When you push down on a block resting on a table, block atoms and table atoms that are in contact with one another

Physics
2 answers:
mylen [45]2 years ago
5 0
Maintain their positions.

Solids are incompressible, just like liquids. The electrostatic forces between the atoms of block and the atoms of table prevent the two objects from moving into one another.
Ulleksa [173]2 years ago
3 0

Answer:

<h2>A. maintain their positions.</h2>

Explanation:

Both objects maintain their position, because the force being applied is in vertical direction, since that is a push down, the reaction force of the table upwards the block doesn't allow movement at all.

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A granite monument has a volume of 25,365.4 cm3. The density of granite is 2.7 g/cm3. Use this information to calculate the mass
Nana76 [90]
V = 25,364.4 cm^3   Is volumer = 2.7g/cm^3      Is density
To calculate mass you use formula:m= V*rTo avoid remembering this formula you can see the type of unit on each given variable. We can see that we have g/cm^3 and cm^3. If we multiply them, we negate cm^3 and cm^3 and we are left with g which is unit for mass.
the answer is :
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6 0
3 years ago
PLS HELP
Ahat [919]
<h3>B. True</h3>

"This was the idea that non-living objects can give rise to living organisms."

7 0
3 years ago
Select the correct answer
Nadya [2.5K]

Answer:

f= 3.0 \times 10 {}^{8} \div 7.0 \times 10 {}^{7} \\ f = 4.28hz

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7 0
2 years ago
A mass is attached to a vertical spring, which then goes into oscillation. At the high point of the oscillation, the spring is i
andrew-mc [135]

Answer:

0.34 sec

Explanation:

Low point of spring ( length of stretched spring ) = 5.8 cm

midpoint of spring = 5.8 / 2 = 2.9 cm

Determine the oscillation period

at equilibrum condition

Kx = Mg

g= 9.8 m/s^2

x = 2.9 * 10^-2 m

k / m = 9.8 / ( 2.9 * 10^-2 ) =  337.93

note : w = \sqrt{k/m}   = \sqrt{337.93} = 18.38 rad/sec

Period of oscillation =  2\pi  / w

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8 0
3 years ago
A small steel roulette ball rolls around the inside of a 30 cm diameter roulette wheel. It is spun at 150 rpm, but is slows to 6
liraira [26]

Solution :

Given

Diameter of the roulette ball = 30 cm

The speed ball spun at the beginning = 150 rpm

The speed of the ball during a period of 5 seconds = 60 rpm

Therefore, change of speed in 5 seconds = 150 - 60

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Therefore,

90 revolutions in 1 minute

or In 1 minute the ball revolves 90 times

i.e. 1 min = 90 rev

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        1 sec = 90/ 60 rec

         5 sec = $\frac{90}{60}\times 5$

                   = 75 rev

Therefore, the ball made 75 revolutions during the 5 seconds.

7 0
2 years ago
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