Answer:
B. The number of wave cycles that pass through a specific point within a given time period.
A) because it is an element.
Explanation: usually when they say pure substance they mean pure element.
Hope this helped!! :)
Answer:
The amount of power will be increased.
Explanation:
If the work remains constant but the time is reduced the power increases. Since power is defined as the relationship between work overtime. By means of the following equation, we can see this relationship.

where:
P = power [Watts]
W = work [J] (units of joules)
t = time [s]
Let's assume with an example the above written.
If we have an electric motor that exerts a work of 950 [J], and the time used is 5 [s], the power is:
![P = 950/5\\P = 190 [W]](https://tex.z-dn.net/?f=P%20%3D%20950%2F5%5C%5CP%20%3D%20190%20%5BW%5D)
Now if we want to accelerate the work done and use 2 seconds for the time, we will have:
![P=950/2\\P=475 [W]](https://tex.z-dn.net/?f=P%3D950%2F2%5C%5CP%3D475%20%5BW%5D)
Complete Question
An L-C circuit has an inductance of 0.350 H and a capacitance of 0.290 nF . During the current oscillations, the maximum current in the inductor is 2.00 A .
What is the maximum energy
stored in the capacitor at any time during the current oscillations?
Express your answer in joules.
Answer:
The value is 
Explanation:
From the question we are told that
The inductance is 
The capacitance is 
The current is 
Generally the maximum energy is mathematically represented as

=> 
=> 
Answer:
α = F/(k×m×r)
Explanation:
When the wheel is pulled to turn in a counterclockwise direction, the wheel will have a moment of inertia given by Iw = k×m×r²
Where k = the radius of gyration of the wheel which is a dimensionless quantity less than one.
m = the mass of the wheel
r = the radius of the wheel
First and foremost, we relate the torque (τ) about the axle of the wheel to the force (F) applied on the wheel and we have that τ = r × F
We then relate the torque on the wheel to the angular acceleration (α), we have that τ = Iw × α, where Iw is the moment of inertia of the wheel as explained above
Substituting for torque τ and moment of inertia I into the above equation we have that
r × F = k×m×r² × α
solving for α we have that
α = r × F /(k×m×r²)
Therefore
α = F/(k×m×r)