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3 years ago

When you push down on a block resting on a table, block atoms and table atoms that are in contact with one another

2 answers:

5 0

Maintain their positions.

Solids are incompressible, just like liquids. The electrostatic forces between the atoms of block and the atoms of table prevent the two objects from moving into one another.

Ulleksa [173]3 years ago

3 0

Answer:

<h2>A. maintain their positions.</h2>

Explanation:

Both objects maintain their position, because the force being applied is in vertical direction, since that is a push down, the reaction force of the table upwards the block doesn't allow movement at all.

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An element carries a_____charge<br>

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Answer:

The charge of an element is equal to the number of protons minus the number of electrons. The number of protons is equal to the atomic number of the element given in the periodic table. The number of electrons is equal to the atomic number minus the charge of the atom.

Explanation:

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What physical property makes metal pots good for cooking

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The metal conducts the heat, which makes cooking easier.

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Naoki's bicycle has a mass of 9 kg. If Naoki sits on her bicycle and starts pedaling with a force of 107.2 N, causing an acceler

Murrr4er [49]

Answer:

Explanation:

F = ma

m = F/a

m = 107.2/1.6 = 67 kg

so Naoki's mass must be the total mass - mass of the bike

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3 years ago

A physical pendulum consists of a meter stick that is pivoted at a small hole drilled through the stick a distance d from the 50

PSYCHO15rus [73]

Answer:

(a). The value of d is 0.056 cm and 1.496 cm.

(b). The time period is 1.35 sec.

Explanation:

Given that,

Length = 50.00 cm

Time period = 2.50 s

Time period of pendulum is defined as the time for one complete cycle.

The period depends on the length of the pendulum.

Using formula of time period

$T=2\pi\sqrt{\dfrac{I}{mgh}}$

Where, I = moment of inertia

We need to calculate the value of d

Using parallel theorem of moment of inertia

$I=I_{cm}+md^2$

For a meter stick mass m , the rotational inertia about it's center of mass

$I_{cm}-\dfrac{mL^2}{12}$

Where, L = 1 m

Put the value into the formula of time period

$T=2\pi\sqrt{\dfrac{\dfrac{mL^2}{12}+md^2}{mgd}}$

$T=2\pi\sqrt{\dfrac{L^2}{12gd}+\dfrac{d}{g}}$

$T^2=4\pi^2(\dfrac{L^2}{12gd}+\dfrac{d}{g})$

Multiplying both sides by d

tex]T^2d=4\pi^2(\dfrac{L^2}{12g}+\dfrac{d^2}{g})[/tex]

$(\dfrac{4\pi^2}{g})d^2-T^2d+\dfrac{\pi^2L^2}{3g}=0$

Put the value of T, L and g into the formula

$4.028d^2-6.25d+0.336=0$

$d = 0.056\ m, 1.496\ m$

The value of d is 0.056 cm and 1.496 cm.

(b). Given that,

L = 50-5 = 45 cm

We need to calculate the time period

Using formula of period

$T=2\pi\sqrt{\dfrac{l}{g}}$

Put the value into the formula

$T=2\pi\sqrt{\dfrac{45\times10^{-2}}{9.8}}$

$T=1.35\ sec$

Hence, (a). The value of d is 0.056 cm and 1.496 cm.

(b). The time period is 1.35 sec.

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3 years ago

You're collecting data in BeyondLabz for an object in free fall, subject to air resistance. How do you know when you've collecte

denis23 [38]

Enough data points would have been collected when specific data for upward and downward motion are collected.

<h3>What is a Data point?</h3>

A data point is a discrete unit of information. This information is always unique.

An object subjected to free fall is under the influence of gravity. An object subjected has different time of motion for upward and downward motion.

Thus, we can conclude that enough data points would have been collected when specific data for upward and downward motion are collected.

Learn more about free fall here: brainly.com/question/10909077

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