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RSB [31]
3 years ago
12

Plz answer the question!

Physics
1 answer:
Sindrei [870]3 years ago
6 0
The light would reflect and go back up in a vortexian loop
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Light in the air is incident at an angle to the surface of (12.0 A) degrees on a piece of glass with an index of refraction of (
Orlov [11]

The question is incomplete. You dis not provide values for A and B. Here is the complete question

Light in the air is incident at an angle to a surface of (12.0 + A) degrees on a piece of glass with an index of refraction of (1.10 + (B/100)). What is the angle between the surface and the light ray once in the glass? Give your answer in degrees and rounded to three significant figures.

A = 12

B = 18

Answer:

18.5⁰

Explanation:

Angle of incidence i = 12.0 + A

A = 12

= 12.0 + 12

= 14

Refractive index u = 1.10 + B/100

= 1.10 + 18/100

= 1.10 + 0.18

= 1.28

We then find the angle of refraction index u

u = sine i / sin r

u = sine24/sinr

1.28 = sine 24 / sine r

1.28Sine r = sin24

1.28 sine r = 0.4067

Sine r = 0.4067/1.28

r = sine^-1(0.317)

r = 18.481

= 18.5⁰

4 0
3 years ago
A scientist in Northern California is studying the tree rings of a very old redwood tree. He notices that the oldest tree rings
Studentka2010 [4]

Answer: colder and drier

Explanation:

Trees don’t grow well in wet climates, nor when they are cold. The wider the rings, the healthier the tree is. Since it was narrow and then wide, was bad climate and then good.

5 0
3 years ago
Read 2 more answers
The radius of The moon is one_fourth and its mass is one eighty-first that of The earth. If The acceleration due to gravity on T
77julia77 [94]
g_{moon} =  g_{earth}*  \frac{( \frac{1}{81} )}{ (\frac{1}{ 4^{2}})}  = g_{earth} *  \frac{16}{81} = 9.8*16/81= 1.935
7 0
3 years ago
Two identical objects A and B fall from rest from different heights to the ground. If object B takes twice as long as object A t
Yuki888 [10]

Answer:

1:4

Explanation:

We have, two identical objects A and B fall from rest from different heights to the ground.

Object B takes twice as long as object A to reach the ground. It is required to find the ratio of the heights from which A and B fell. Let h_A\ \text{and}\ h_B are the height for A and B respectively. So,

\dfrac{h_A}{h_B}=\dfrac{(1/2)gt_A^2}{(1/2)gt_B^2}\\\\\dfrac{h_A}{h_B}=\dfrac{t_A^2}{t_B^2}

We have,

t_B=2t_A

So,

\dfrac{h_A}{h_B}=\dfrac{t_A^2}{(2t_B)^2}\\\\\dfrac{h_A}{h_B}=\dfrac{1}{4}

So, the ratio of the heights from which A and B fell is 1:4.

7 0
3 years ago
Need help with this question ​
lakkis [162]

Answer:

1.39m

Explanation:

5 0
2 years ago
Read 2 more answers
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