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Ede4ka [16]
3 years ago
9

The value of x in the diagram is ___ °. 40 50 90 180

Physics
1 answer:
olga2289 [7]3 years ago
6 0
The value of x is 40°. Because, we know that a half circle equals 180 degrees. A quarter circle equals 90 degrees. 50+40=90. The reflection area has the same degree amount, so the angle is 40 °. Let me know if this helps you!
You might be interested in
A tree is 257 ft high. To the nearest tenth of a meter, how tall is it in meters? There are 3.28 ft in 1 m.
olga2289 [7]

Answer:

Height of tree = 78.35 meters.

Explanation:

We have

          1 meter = 3.28 feet

That is

          1 ft = \frac{1}{3.28}=0.3048m

Here height of tree = 257 ft

Height of tree = 257 x 0.3048 = 78.35 m

Height of tree = 78.35 meters.

7 0
3 years ago
Which observational tool helped astronomers Arno Penzias and Robert Wilson discover the
iren2701 [21]

Answer:

A radio telescope helped the astronomers discover the CMB.

Explanation:

  • Penzias and Wilson while experimenting with a radio telescope in 1964, accidentally discovered the radiation that exists universally also known as the CMB.
  • This was used to support the "Big Bang Theory" and not the "Steady State Theory"
  • CMB is the faint cosmic radiation that fills up the universe. It provides important data for understanding early universe.
  • This data tells us about the composition of the universe and its age which raises new questions about the universe.
3 0
3 years ago
Desde una altura de 120 m se deja caer un cuerpo. Calcular a los 2,5 s i) la rapidez que lleva; ii) cuánto ha descendido; iii) c
stira [4]

Answer:

i) 24.5 m/s

ii) 30,656 m

iii) 89,344 m

Explanation:

Desde una altura de 120 m se deja caer un cuerpo. Calcule a 2.5 s i) la velocidad que toma; ii) cuánto ha disminuido; iii) cuánto queda por hacer

i) Los parámetros dados son;

Altura inicial, s = 120 m

El tiempo en caída libre = 2.5 s

De la ecuación de caída libre, tenemos;

v = u + gt

Dónde:

u = Velocidad inicial = 0 m / s

g = Aceleración debida a la gravedad = 9.81 m / s²

t = Tiempo de caída libre = 2.5 s

Por lo tanto;

v = 0 + 9.8 × 2.5 = 24.5 m / s

ii) El nivel que el cuerpo ha alcanzado en 2.5 segundos está dado por la relación

s = u · t + 1/2 · g · t²

= 0 × 2.5 + 1/2 × 9.81 × 2.5² = 30.656 m

iii) La altura restante = 120 - 30.656 = 89.344 m.

6 0
3 years ago
A projectile is fired horizontally from a height of 78.4 m at a speed of 300 m/sec. How far did it travel horizontally before hi
Mice21 [21]

Answer:

Explanation:

Using the formula for calculating range expressed as;

R = U√2H/g

U is the speed = 300m/s

H is the maximum height = 78.4m

g is the acceleration due to gravity = 9.8m/s²

Substitute into the fromula;

R = 300√2(78.4)/9.8

R = 300 √(16)

R = 300*4

R = 1200m

Hence the projectile travelled 1200m before hitting the ground

3 0
3 years ago
Fiberglass, an insulator, can be found in the wals and roofs of some houses and buildings. Why would an insulator be needed insi
GREYUIT [131]

It keeps the heat inside of the building

5 0
3 years ago
Read 2 more answers
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