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3 years ago

Solve the system of equations

Mathematics

2 answers:

FromTheMoon [43]3 years ago

5 0

Answer:

x=18

Step-by-step explanation:

add 2y to both sides 5x=2y+88

subtract 88 from both sides 2y=5x-88

substitute 2y in the second equation for 5x-88

3x+10x-176=58

add like terms 13x-176=58

add 176 both sides

13x=234

x=18

suter [353]3 years ago

3 0

Answer:

( 18, -6.5 )

Step-by-step explanation:

First choose which method you plan on using: Substitution or Elimation. I chose elimination based off preference.

How to solve using Elimination:

5x -2y = 88 (multiply every number in this equation by two)

3x+4y=58

10x -4y = 176

3x+4y=58 (combine these two equations)

13x = 234 (isolate x by dividing by 13 on both sides)

x = 18 (this is your value for x)

3(18) +4y=58 (plug in for x)

54+4y=28 (solve)

4y = -26 (subtract 54 from both sides)

y = -6.5 (this is y)

write answer in (x, y) format

( 18, -6.5 )

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3 years ago

Read 2 more answers

Find an equation for those points P such that the distance from P to A(0, 1, 2) is equal to the distance from P to B(6, 4, 2). W

suter [353]

Answer: The required equation for points P is $4x+2y=17.$

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To find the equation for points P such that the distance of P from both A and B are equal.

We know that the distance between two points R(a, b, c) and S(d, e, f) is given by

$RS=\sqrt{(d-a)^2+(e-b)^2+(f-c)^2}.$

Let the point P be represented by (x, y, z).

According to the given information, we have

$PA=PB\\\\\Rightarrow \sqrt{(x-0)^2+(y-1)^2+(z-2)^2}=\sqrt{(x-6)^2+(y-4)^2+(z-2)^2}\\\\\Rightarrow x^2+y^2-2y+1+z^2-4z+4=x^2-12x+36+y^2-8y+16+z^2-4z+4~~~~~~~[\textup{Squaring both sides}]\\\\\Rightarrow -2y+1=-12x-8y+52\\\\\Rightarrow 12x+6y=51\\\\\Rightarrow 4x+2y=17.$

Thus, the required equation for points P is $4x+2y=17.$

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