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kvasek [131]
2 years ago
6

Help :) you will receive 15 points <3

Mathematics
1 answer:
Cloud [144]2 years ago
6 0
Yea that answer up there is a bot and the file is spy ware don’t download it
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Grandma is trying out a new recipe for raisin bread. Each batch of bread dough makes three loaves, and each loaf contains 15 sli
Tom [10]

Answer:

0.108

Step-by-step explanation:

Using the poisson probability process :

Where :

P(x =x) = (e^-λ * λ^x) ÷ x!

Given that :

Each batch of bread = 3 loaves

Each loaf = 15 slices

Total slice per batch = 15 * 3 = 45 slices

Number of raising added = 100

Average number of raisin per slice, λ = 100/45 = 20/9

Hence,

Probability that a randomly chosen slice has no raising :

P(x = 0) = (e^-λ * λ^x) ÷ x!

P(x = 0) = (e^-(100/45) * (100/45)^0) ÷ 0!

P(x = 0) = (0.1083680 * 1) / 1

P(x = 0) = 0.108

8 0
3 years ago
Two researchers conducted a study in which two groups of students were asked to answer 42 trivia questions from a board game. Th
Verizon [17]

Answer:

(21.9-19.8) -1.966\sqrt{\frac{3.4^2}{200} +\frac{3.5^2}{200}}= 1.422

(21.9-19.8) -1.966 \sqrt{\frac{3.4^2}{200} +\frac{3.5^2}{200}}= 2.778

And we are 95% confident that the true difference means are between 1.422 \leq \mu_1 -\mu_2 \leq 2.778

Step-by-step explanation:

We know the following info:

\bar X_1 = 21.9 sample mean for group 1

\bar X_2 = 19.8 sample mean for group 2

s_1 = 3.4 sample standard deviation for group 1

s_2 = 3.5 sample standard deviation for group 2

n_1 = 200 sample size group 1

n_2 = 200 sample size group 2

We want to find a confidence interval for the difference of means and the correct formula to do this is:

(\bar X_1 -\bar X_2) \pm t_{\alpha/2} \sqrt{\frac{s^2_1}{n_1} +\frac{s^2_2}{n_2}}

Now we just need to find the critical value. The confidence level is 0.95 then the significance is 1-0.95 =0.05 and \alpha/2 =0.025. The degrees of freedom are given by:

df= n_1 +n_2 -2= 200+200-2= 398

The critical value for this case would be :t_{\alpha/2}=1.966  

And replacing into the confidence interval formula we got:

(21.9-19.8) -1.966\sqrt{\frac{3.4^2}{200} +\frac{3.5^2}{200}}= 1.422

(21.9-19.8) -1.966 \sqrt{\frac{3.4^2}{200} +\frac{3.5^2}{200}}= 2.778

And we are 95% confident that the true difference means are between 1.422 \leq \mu_1 -\mu_2 \leq 2.778

5 0
3 years ago
Saul decides to use the IQR to measure the spread of the data. Saul calculates the IQR of the data set to be 27
german

Answer:

n = 78

Step-by-step explanation:

IQR is the interquartile range of the data set.

So Saul had already arranged the data in order, that is the first step when calculating the interquartile range.

25, 30, 50, 50, 50, 50, 56, n., 250

Next, is to find the median so we could easily separate the data into quartiles.

The median of the data 25, 30, 50, 50, 50, 50, 56, n., 250 = 50

Then, arrange the data into the first quartile and the third quartile

first quartile = 25, 30, 50, 50

third quartile = 50, 56, n., 250

first quartile median = 30 + 50 = 80/2 = 40

third quartile = 56 + n /2

The interquartile range formula is the first quartile subtracted from the third quartile:

IQR = Q3 – Q1.

Since 27 is the interquartile range, n=

27 = (56 + n /2) - 40

Use 2 to multiply through to eliminate the denominator

54 = (56 + n) - 80

n = 78

5 0
3 years ago
can you guys help me with letter c? (don’t be like oooooh this is SOOO easy because i’m just in 6th grade.) please and thank you
Alexxandr [17]
6 weeks
1150-370=780
780 divided by 130=6
8 0
3 years ago
Read 2 more answers
A recipe makes 6 2/3 cups. The serving size is 5/6 cup. How many servings does the recipe make?
Dmitry [639]
Answer is a I just know
6 0
3 years ago
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