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zvonat [6]
3 years ago
5

In the student council election, Davina received 50 votes, Binh received 40 votes and Eden received 80 votes. What is the ratio

of Binh’s votes to Davina’s votes in simplest form?
In the student council election, Davina received 50 votes, Binh received 40 votes and Eden received 80 votes. What is the ratio of Binh’s votes to Davina’s votes in simplest form?
A
5 to 4
B
4 to 5
C
1 to 2
D
4 to 17
Mathematics
2 answers:
ira [324]3 years ago
7 0

Answer: C

I hope this helps. Lol I solved it easily. Good luck

storchak [24]3 years ago
7 0

Answer:

B. 4:5 or 4 to 5

Step-by-step explanation:

It would be 40:50 but because it’s simplified your answer would be 4:5. Every 40 votes Binh got Davina got 50.

Hope this helps and is correct! Good luck! :)

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7 because the square root of 49 is 7, so its approximately 7.
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4x2-36x+80=0
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The Sky Ranch is a supplier of aircraft parts. Included in stock are 10 altimeters that are correctly calibrated and two that ar
mart [117]

Answer:  a) 0.545,b) 0.41, c) 0.045, d) not possible.

Step-by-step explanation:

The Sky Ranch is a supplier of aircraft parts. Included in stock are 10 altimeters that are correctly calibrated and two that are not. Three altimeters are randomly selected without replacement. Let the random variable

x represent the number that are not correctly calibrated.

Complete the probability distribution table.

x={0,1,2,3}

P(x=0)=?

P(x=1)=?

P(x=2)=?

P(x=3)=?

Since we have given that

n = 12

number of good one = 3 from 10

number of bad one = 2

So, P(X=0)=\dfrac{^{10}C_3\times ^2C_0}{^{12}C_3}=\dfrac{120}{220}=0.545

P(X=1) = \dfrac{^{10}C_2\times ^2C_1}{^{12}C_3}=\dfrac{90}{220}=0.41

P(X=2)=\dfrac{^{10}C_1\times ^2C_2}{^{12}C_3}=\dfrac{10}{220}=0.045

P(X=3) is not possible.

Hence, a) 0.545,b) 0.41, c) 0.045, d) not possible.

5 0
3 years ago
19 POINTS HELP PLEASE! Complete the table and pattern. Determine the common difference. Write the explicit rule.
Sonbull [250]

4.

a_1=-20,\ a_3=-15\\\\2d=a_3-a_1\to 2d=-15-(-20)\to2d=-15+20\to2d=5\to d=2.5\\\\a_n=a_1+(n-1)d\to a_n=-20+(n-1)(2.5)=-20+2.5n-2.5=2.5n-22.5\\\\a_2=2.5(2)-22.5=5-22.5=-17.5\\\\a_4=2.5(4)-22.5=10-22.5=-12.5\\\\a_6=2.5(6)-22.5=15-22.5=-7.5

<u>n   |    1     |   2    |   3   |   4   |   5    |   6   |</u>

f(n)|  -20  | -17.5 |  -15  |-12.5|  -10  | -7.5 |

First term: -20     Common Difference: 2.5

Explicit Rule:  a_n=2.5n-22.5       Recursive Rule: a_1=-20,\ a_n=a_{n-1}+2.5

5.

a_1=123,\ a_2=131\\\\d=a_2-a_1\to d=131-123=8\\\\a_n=a_1+(n-1)d\to a_n=123+(n-1)(8)=123+8n-8=8n+115\\\\a_3=8(3)+115=24+115=139\\\\a_5=8(5)+115=40+115=155\\\\a_6=8(6)+115=48+115=163

<u>n   |    1     |   2    |   3   |   4   |   5    |   6   |</u>

f(n)|  123  |  131   | 139 | 147  |  155  | 163 |

First term: 123      Common Difference: 8

Explicit Rule:  a_n=8n+115       Recursive Rule: a_1=20,\ a_n=a_{n-1}+8

3 0
3 years ago
Find the probability of being dealt a "jacks over aces" full house (three jacks and two aces). (Round your answer to six decimal
Stella [2.4K]

Answer:

1.500000

Step-by-step explanation:

jacks over aces

3÷2

=1.5

correct to six decimal places

1.500000

6 0
3 years ago
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