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3 years ago

What is 15+cj to the 3rd power when c=6 and j=5

Mathematics

1 answer:

exis [7]3 years ago

3 0

1)( 15+cj)^3 for j = 5 and c = , ( 15+6*5)^3 = (45)^3 = 91125

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Answer:

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Step-by-step explanation:

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Troyanec [42]

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dolphi86 [110]

Answer:

10 miles.

Step-by-step explanation:

Let x be the number of miles on Henry's longest race.

We have been given that Henry ran five races, each of which was a different positive integer number of miles.

We can set an equation for the average of races as:

$\frac{\text{The sum distances of 5 races}}{5}=4$

As distance covered in each race is a different positive integer, so let his first four races be 1, 2, 3, 4.

Now let us substitute the distances of 5 races as:

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$\frac{10+x}{5}=4$

Let us multiply both sides of our equation by 5.

$\frac{10+x}{5}*5=4*5$

$10+x=20$

Let us subtract 10 from both sides of our equation.

$10-10+x=20-10$

$x=10$

Therefore, the maximum possible distance of Henry's longest race is 10 miles.

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3 years ago

Mr. Nelson bought a car for $20,000 with a 5% interest rate.

MrMuchimi

Answer:

Step-by-step explanation:

do you know the answer

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sergey [27]

Answer:

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Step-by-step explanation:

Its given:

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3 years ago