D is correct. f(-2) the number in the bracket is an input so..
whenever you see an X in the function replace it with -2
f(-2)=2*3^-2
3^-2 is 1/9
1/9 * 2 is simply 2/9
so D is correct
Answer:
Step-by-step explanation:
hello,
I understand that there are only 4 cards and then the player draw a card out of the 4 cards, replace it so the second draw is still out of the 4 cards
<u>How many ways can you draw two cards?</u>
as the first card is replaced, this is 4*4=16
so there is 16 possibles ways
hearts hearts
hearts clubs
hearts diamonds
hearts spades
clubs hearts
clubs clubs
clubs diamonds
clubs spades
diamonds hearts
diamonds clubs
diamonds diamonds
diamonds spades
spades hearts
spades clubs
spades diamonds
spades spades
<u>out of these 16 ways, how many have same colour for both cards?</u>
I assume that there are only two colours Red and Black, so we can have
only 8 ways so the first probability is 8/16 = 1/2
<u>out of these 16 ways, how many are red ace first and black ace?</u>
There are 4 ways so the probability is 4/16 = 1/4
hope this helps
Alright so the answer would be letter B, because
win-to-loss
49 to 21 (You can determine her losses by subtracted the number of wins from her total number of games played)
Now you must simplify your answer
7 is the greatest common factor (GCF) of both 49 and 21
Now divide both 49 and 21 by 7 to get
7 to 3
6/20 chance or simplified would be 3/10. Answer [D] is correct.
Answer:
96 i think
Step-by-step explanation:
i did 480/5
